What is 5,382,619 rounded to the nearest 1,000

Mathematics

1 answer:

Aliun [14]3 years ago

5 0

The answer is 5,383,000

You might be interested in

Plz help me with the ones that are circled

Alisiya [41]

Your answer for your question is going to be.... um.... sorry I forgot

3 0

3 years ago

Use chain rule to find dw/dt w=ln(x^2 + y^2 + z^2)^(1/2) , x=sint, y=cost, z=tant

son4ous [18]

The chain rule states that

$\dfrac{\mathrm dw}{\mathrm dt}=\dfrac{\partial w}{\partial x}\dfrac{\mathrm dx}{\mathrm dt}+\dfrac{\partial w}{\partial y}\dfrac{\mathrm dy}{\mathrm dt}+\dfrac{\partial w}{\partial z}\dfrac{\mathrm dz}{\mathrm dt}$

Since $\ln(x^2+y^2+z^2)^{1/2}=\dfrac12\ln(x^2+y^2+z^2)$ , you have

$\dfrac{\partial w}{\partial x}=\dfrac x{x^2+y^2+z^2}$
$\dfrac{\partial w}{\partial x}=\dfrac y{x^2+y^2+z^2}$
$\dfrac{\partial w}{\partial z}=\dfrac z{x^2+y^2+z^2}$

and

$\dfrac{\mathrm dx}{\mathrm dt}=\cos t$
$\dfrac{\mathrm dy}{\mathrm dt}=-\sin t$
$\dfrac{\mathrm dz}{\mathrm dt}=\sec^2t$

Also, since $x^2+y^2+z^2=\sin^2t+\cos^2t+\tan^2t=1+\tan^2t=\sec^2t$ , the derivative is

$\dfrac{\mathrm dw}{\mathrm dt}=\dfrac{\sin t\cos t}{\sec^2t}-\dfrac{\sin t\cos t}{\sec^2t}+\dfrac{\tan t\sec^2t}{\sec^2t}$
$\dfrac{\mathrm dw}{\mathrm dt}=\tan t$

4 0

3 years ago

The probability distribution table shows the proportion of people living in the five different regions of a city there are now 4

const2013 [10]

Since there are a total of 4,200 residents and the question is asking for the amount in the south region, take the distribution number from the chart, 0.16, and multiply it by 4,200.
4200 ×.16 = 672

672 residents

4 0

3 years ago

Read 2 more answers

A rectangular living room has an area of 425 ft.² the width of the room is 17 feet

yanalaym [24]

What are you trying to find? If it’s the length, just divide 425 by 17, which is 35 ft!

6 0

3 years ago

Item 4

Simora [160]

Answer:

270 s