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3 years ago

Which of the following is equivalent to 5/13^3

Mathematics

1 answer:

lys-0071 [83]3 years ago

8 0

Answer:

.00227 or 5/2197

Step-by-step explanation:

following the basic rules of PEMDAS, we know that we have to solve for the exponent first.

so.... 5/2197

as a decimal, this is .00227...

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Help two helpless triangles?

Illusion [34]

Answer:

see below

Step-by-step explanation:

Angle ACE = DCE since they are vertical angles

Angle A = Angle E parallel lines cut by a transversal form congruent alternate interior angles

Angle B = Angle D parallel lines cut by a transversal form congruent alternate interior angles

When all three angles are equal, the triangles are similar.

We can use ratios to find DE

DE CE

------- = ----------

AB AC

DE 8

------- = ----------

12 10

Using cross products

10 DE = 8*12

10 DE = 96

Divide by 10

DE = 9.6

3 0

3 years ago

Read 2 more answers

Help!!

Makovka662 [10]

Answer:

look at the picture i have sent

8 0

3 years ago

Add.<br> (4x2 - 2x) + (5x-7)

Sloan [31]

Answer:

4x²+3x-7 is the answer

Step-by-step explanation:

=(4x²-2x)+(5x-7)

opening brackets

=4x²-2x+5x-7

=4x²+3x-7

i hope this will help you :)

7 0

4 years ago

What is 6 divided by 812

maksim [4K]

6 divided by 812 is very difficult to do without using a calculator - I would suggest the bus shelter method, as I've shown in the photo attached, but it is still quite difficult to use that method without a calculator.

<em>If</em>, however, you mean 812 divided by 6, that is a lot easier to calculate using the bus shelter method - so, just in case, I've attached the method for that too.

6 divided by 812 = 0.007389...

4 0

3 years ago

Prove that<br>{(tanθ+sinθ)^2-(tanθ-sinθ)^2}^2 =16(tanθ+sinθ)(tanθ-sinθ)

USPshnik [31]

First, expand the terms inside the bracket you will get

$(( \tan {}^{2} (x) + 2 \tan(x) \sin(x) + \sin {}^{2} (x) - ( \tan {}^{2} (x) - 2 \tan(x) + \sin {}^{2} (x) ) {}^{2} = 16( \tan(x) + \sin(x) )( \tan(x) - \sin(x) )$

$( 4 \tan(x) \sin(x) ) {}^{2} = 16( \tan(x) + \sin(x) )( \tan(x) - \sin(x) )$

$16 \tan {}^{2} (x) \sin {}^{2} (x) = 16( \tan(x) + \sin(x) )( \tan(x) - \sin(x) )$

$16 \tan {}^{2} (x) (1 - \cos {}^{2} (x) ) = 16 (\tan(x) + \sin(x) )( \tan(x) - \sin(x) )$

$16( \tan {}^{2} (x) - \frac{ \sin {}^{2} (x) \cos {}^{2} ( {x}^{} ) }{ \cos {}^{2} (x) }$

$16( \tan {}^{2} (x) - \sin {}^{2} (x) ) = 16( \tan(x) + \sin(x) )( \tan(x) - \sin(x) )$

$16( \tan(x) + \sin(x) )( \tan(x) - \sin(x) = 16( \tan(x) + \sin(x) )( \tan(x) - \sin(x) )$

5 0

2 years ago