Answer:
(Assuming you want your answer in radians)
If you want the answer in degrees just multiply your answer in radians by 
giving you:
.
We can do this since 
(half the circumference of the unit circle is equivalent to 180 degree rotation).
Step-by-step explanation:
is going to output an angle measurement in ![[0,\pi]](https://tex.z-dn.net/?f=%5B0%2C%5Cpi%5D)
.
So we are looking to solve the following equation in that interval:
.
This happens in the second quadrant on the given interval.
The solution to the equation is .
So we are saying that 
implies 
since ![\frac{3\pi}{4} \in [0,\pi]](https://tex.z-dn.net/?f=%5Cfrac%7B3%5Cpi%7D%7B4%7D%20%5Cin%20%5B0%2C%5Cpi%5D)
.
Answer is .
Answer:
Step-by-step explanation:
The attached photo shows the diagram of quadrilateral QRST with more illustrations.
Line RT divides the quadrilateral into 2 congruent triangles QRT and SRT. The sum of the angles in each triangle is 180 degrees(98 + 50 + 32)
The area of the quadrilateral = 2 × area of triangle QRT = 2 × area of triangle SRT
Using sine rule,
q/SinQ = t/SinT = r/SinR
24/sin98 = QT/sin50
QT = r = sin50 × 24.24 = 18.57
Also
24/sin98 = QR/sin32
QR = t = sin32 × 24.24 = 12.84
Let us find area of triangle QRT
Area of a triangle
= 1/2 abSinC = 1/2 rtSinQ
Area of triangle QRT
= 1/2 × 18.57 × 12.84Sin98
= 118.06
Therefore, area of quadrilateral QRST = 2 × 118.06 = 236.12
Answer:
Vertex: (3, 23)
Step-by-step explanation:
a = -1 b = 6 c = 14
x vertex = 
