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Vanyuwa [196]
2 years ago
5

Calculating cos-1 ( help is gladly appreciated :) )

Mathematics
1 answer:
Alekssandra [29.7K]2 years ago
4 0

Answer:

\frac{3\pi}{4}

(Assuming you want your answer in radians)

If you want the answer in degrees just multiply your answer in radians by \frac{180^\circ}{\pi} giving you:

\frac{3\pi}{4} \cdot \frac{180^\circ}{\pi}=\frac{3(180)}{4}=135^{\circ}.

We can do this since \pi \text{ rad }=180^\circ (half the circumference of the unit circle is equivalent to 180 degree rotation).

Step-by-step explanation:

\cos^{-1}(x) is going to output an angle measurement in [0,\pi].

So we are looking to solve the following equation in that interval:

\cos(x)=-\frac{\sqrt{2}}{2}.

This happens in the second quadrant on the given interval.

The solution to the equation is \frac{3\pi}{4}.

So we are saying that \cos(\frac{3\pi}{4})=\frac{-\sqrt{2}}{2} implies \cos^{-1}(\frac{-\sqrt{2}}{2})=\frac{3\pi}{4} since \frac{3\pi}{4} \in [0,\pi].

Answer is \frac{3\pi}{4}.

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3 years ago
'-(x^2/2)-x-(5/2)' simplify
Lilit [14]

Answer:

-1 by x^2/2

Step-by-step explanation:

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6 0
3 years ago
For each container of tea, McKenzie uses 16 tea bags and 3 cups of sugar. If McKenzie uses 64 tea bags, how many cups of sugar w
cestrela7 [59]
So tis is a ratio  16 is to 3 or 16:3
if use 64 tea bags then how many cups of sugar so
turn 16:3 into fraction
16:3=16/3 or 3/16, it doesn't matter
then you want to find 64:x or 64/x or x/64

we know that 16/3=64/x because it tis an equivalent ratio
so 16/3=64/x
multiply both sdies by (3 times x)
16 times x times 3/3=64 times 3 times x/x
16 times x=64 times 3
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5 0
3 years ago
What does 1/4+1/3 equal
grandymaker [24]

Answer:

7/12

Step-by-step explanation:

1/4+1/3

the LCM is 12

4+3/7=7/12

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8 0
3 years ago
What are the roots of the equation x^2+6x-9=10?
Ronch [10]

Answer:

-3+2sqrt7

-3-2sqrt7

Step-by-step explanation:

x^2+6x-9=10

x^2+6x-9-10=0

x^2+6x-19=0

ax^2+bx+c=0

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As cannot be solved by completing square we will use quadratic equation

x= (-b+sqrt(b^2-4ac))/2a     and      x= (-b-sqrt(b^2-4ac))/2a

x= (-6+sqrt(6^2-4*-19))/2     and      x= (-6-sqrt(6^2-4*-19))/2

x=(-6+sqrt(36+76))/2           and      x=(-6-sqrt(36+76))/2

x=(-6+4sqrt7)/2                   and       x=(-6-4sqrt7)/2

x=(-3+2sqrt7)                       and      x=(-3-2sqrt7)

x=2.29                                 and      x= -8.29

3 0
3 years ago
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