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givi [52]
3 years ago
14

Solve for x: |4x + 12| = 16

Mathematics
2 answers:
irina1246 [14]3 years ago
7 0
Solve Absolute value
4x + 12 = 16 or <span>4x + 12 = -1<span>6
</span></span>===============================================
1.) 4x+12=<span>16
Subtract 12 from both sides
</span><span><span>4x+12-1</span>2</span>=<span>16-12
</span>4x = 4
Divide by 4
4x ÷ 4 = 4 ÷ 4
x = 1
=================================================================
2.) 4x+12=-<span>16
</span>Subtract 12 from both sides
<span><span>4x+12-</span>12</span>=-<span>16-12
</span><span>4x</span>=-<span><span>28
</span></span>Divide each side by 4
4x ÷ 4 = -28 ÷ 4
x = -7
================================================================
X = 1 and x = -7 is your answer
JulijaS [17]3 years ago
6 0
4x+12=16
4x=4
x=1

or

-(4x+12)=16
-4x-12=16
-4x=28
x=-7

answer Choice C is correct
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Determine whether the following lines represented by the vector equations below intersect, are parallel, are skew, or are identi
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Answer:

r(t) and s(t) are parallel.

Step-by-step explanation:

Given that :

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r(t)=⟨1−t,3+2t,−3t⟩

s(t)=⟨2t,−3−4t,3+6t⟩

The objective is to determine if the following lines represented by the vector equations below intersect, are parallel, are skew, or are identical.

NOTE:

Two lines will be parallel if \dfrac{x_1}{x_2}= \dfrac{y_1}{y_2}= \dfrac{z_1}{z_2}

here;

d_1 = (-1, \ 2, \ -3)

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r(t) = \dfrac{x-1}{-1} = \dfrac{y-3}{2}=\dfrac{z-0}{-3} = t

d_2 =(2, \ -4, \  +6)

s(t) = \dfrac{x-0}{2} = \dfrac{y+5}{-4}=\dfrac{z-3}{6} = t

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6 0
3 years ago
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