Jayce sold 28 bc $210/84 bars = $2.50 per bar. $70/2.50 = 28 bars
Answer:
Quantity of heat needed (Q) = 722.753 × 10³
Step-by-step explanation:
According to question,
Mass of water (m) = 40 kg
Change in temperature ( ΔT) = 18°c
specific heat capacity of water = 4200 j kg^-1 k^-1
The specific heat capacity is the amount of heat required to change the temperature of 1 kg of substance to 1 degree celcius or 1 kelvin .
So, Heat (Q) = m×s×ΔT
Or, Q = 40 kg × 4200 × 18
or, Q = 3024 × 10³ joule
Hence, Quantity of heat needed (Q) = 3024 × 10³ joule
In calories 4.184 joule = 1 calorie
So, 3024 × 10³ joule = 722.753 × 10³
The water in the aquarium is a rectangular prism with dimensions 20, 12 and h (where the height is unknown).
We know that the volume is the product of the dimensions, and that it is 2400, so we have
The answer C -20
hope this helped
Answer: 119
Step-by-step explanation: base * height / 2
14*17/2=119. can i get Brainliest please
