Please help!!<br> Will mark brainliest

Noah will select a letter at random from the word "FLUTE." Lin will select a letter at random from the word "CLARINET." Which pe

Murljashka [212]

Answer:

Noah

Step-by-step explanation:

Lin's word contains more letters that aren't E.

8 0

3 years ago

Read 2 more answers

I want the anwcers plzzZzzzzzzzzzzzzzzzzzzzzzz

tino4ka555 [31]

Answer:

Step-by-step explanation:

A: 40

B: 21

8 0

3 years ago

) Use the Laplace transform to solve the following initial value problem: y′′−6y′+9y=0y(0)=4,y′(0)=2 Using Y for the Laplace tra

artcher [175]

Answer:

$y(t)=2e^{3t}(2-5t)$

Step-by-step explanation:

Let Y(s) be the Laplace transform Y=L{y(t)} of y(t)

Applying the Laplace transform to both sides of the differential equation and using the linearity of the transform, we get

L{y'' - 6y' + 9y} = L{0} = 0

(*) L{y''} - 6L{y'} + 9L{y} = 0 ; y(0)=4, y′(0)=2

Using the theorem of the Laplace transform for derivatives, we know that:

$\large\bf L\left\{y''\right\}=s^2Y(s)-sy(0)-y'(0)\\\\L\left\{y'\right\}=sY(s)-y(0)$

Replacing the initial values y(0)=4, y′(0)=2 we obtain

$\large\bf L\left\{y''\right\}=s^2Y(s)-4s-2\\\\L\left\{y'\right\}=sY(s)-4$

and our differential equation (*) gets transformed in the algebraic equation

$\large\bf s^2Y(s)-4s-2-6(sY(s)-4)+9Y(s)=0$

Solving for Y(s) we get

$\large\bf s^2Y(s)-4s-2-6(sY(s)-4)+9Y(s)=0\Rightarrow (s^2-6s+9)Y(s)-4s+22=0\Rightarrow\\\\\Rightarrow Y(s)=\frac{4s-22}{s^2-6s+9}$

Now, we brake down the rational expression of Y(s) into partial fractions

$\large\bf \frac{4s-22}{s^2-6s+9}=\frac{4s-22}{(s-3)^2}=\frac{A}{s-3}+\frac{B}{(s-3)^2}$

The numerator of the addition at the right must be equal to 4s-22, so

A(s - 3) + B = 4s - 22

As - 3A + B = 4s - 22

we deduct from here

A = 4 and -3A + B = -22, so

A = 4 and B = -22 + 12 = -10

It means that

$\large\bf \frac{4s-22}{s^2-6s+9}=\frac{4}{s-3}-\frac{10}{(s-3)^2}$

and

$\large\bf Y(s)=\frac{4}{s-3}-\frac{10}{(s-3)^2}$

By taking the inverse Laplace transform on both sides and using the linearity of the inverse:

$\large\bf y(t)=L^{-1}\left\{Y(s)\right\}=4L^{-1}\left\{\frac{1}{s-3}\right\}-10L^{-1}\left\{\frac{1}{(s-3)^2}\right\}$

we know that

$\large\bf L^{-1}\left\{\frac{1}{s-3}\right\}=e^{3t}$

and for the first translation property of the inverse Laplace transform

$\large\bf L^{-1}\left\{\frac{1}{(s-3)^2}\right\}=e^{3t}L^{-1}\left\{\frac{1}{s^2}\right\}=e^{3t}t=te^{3t}$

and the solution of our differential equation is

$\large\bf y(t)=L^{-1}\left\{Y(s)\right\}=4L^{-1}\left\{\frac{1}{s-3}\right\}-10L^{-1}\left\{\frac{1}{(s-3)^2}\right\}=\\\\4e^{3t}-10te^{3t}=2e^{3t}(2-5t)\\\\\boxed{y(t)=2e^{3t}(2-5t)}$

5 0

3 years ago

Two lengths of a triangle are shown.

Solnce55 [7]

Answer:

11 ft

Step-by-step explanation:

Given the two lengths of a triangle as

AB = 6ft

AC = 6ft

This is an isosceles triangle because only 2 sides are equal.

In an isosceles triangle, the sum of 2 (sides) lengths must be greater than the other length.

Therefore, let's assume the following:

i) AC + AB > BC

6 + 6 > BC

12 > BC (BC is less than 12)

BC < 12

ii) BC + AC > AB

BC + 6 > 6

BC > 6 - 6

BC > 0

Therefore the range of values for BC =

0 < BC < 12

Since BC must be bigger than one of the lengths and it must also be less than the sum of the 2 sides. The length of BC could be 11 because it is less than (6+6) 12 and greater than 6.

5 0

2 years ago

If you vertically stretch the exponential function f(x)=2^x by a factor of 3, what is the equation of the new function

AleksAgata [21]

Answer:

$y=3*2^{x}$

Step-by-step explanation:

A vertical stretch of a function means the output values have changed by a factor of 3 or multiplication by 3. Recall, an exponential function has the basic form

$y=ab^{2}$ .

If our equation is $f(x)=2^x$ , then a=1. To stretch it vertically by a factor of 3, we multiply a by 3. So 1(3)=3. The value of a now becomes 3.

$y=3*2^{x}$

7 0

3 years ago

Please help!! Will mark brainliest