1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
RoseWind [281]
2 years ago
9

Please help!! Will mark brainliest

Mathematics
1 answer:
Over [174]2 years ago
8 0
Y would equal to -5. hope this helps
You might be interested in
Noah will select a letter at random from the word "FLUTE." Lin will select a letter at random from the word "CLARINET." Which pe
Murljashka [212]

Answer:

Noah

Step-by-step explanation:

Lin's word contains more letters that aren't E.

8 0
3 years ago
Read 2 more answers
I want the anwcers plzzZzzzzzzzzzzzzzzzzzzzzzz
tino4ka555 [31]

Answer:

Step-by-step explanation:

A: 40

B: 21

8 0
3 years ago
) Use the Laplace transform to solve the following initial value problem: y′′−6y′+9y=0y(0)=4,y′(0)=2 Using Y for the Laplace tra
artcher [175]

Answer:

y(t)=2e^{3t}(2-5t)

Step-by-step explanation:

Let Y(s) be the Laplace transform Y=L{y(t)} of y(t)

Applying the Laplace transform to both sides of the differential equation and using the linearity of the transform, we get

L{y'' - 6y' + 9y} = L{0} = 0

(*) L{y''} - 6L{y'} + 9L{y} = 0 ; y(0)=4, y′(0)=2  

Using the theorem of the Laplace transform for derivatives, we know that:

\large\bf L\left\{y''\right\}=s^2Y(s)-sy(0)-y'(0)\\\\L\left\{y'\right\}=sY(s)-y(0)

Replacing the initial values y(0)=4, y′(0)=2 we obtain

\large\bf L\left\{y''\right\}=s^2Y(s)-4s-2\\\\L\left\{y'\right\}=sY(s)-4

and our differential equation (*) gets transformed in the algebraic equation

\large\bf s^2Y(s)-4s-2-6(sY(s)-4)+9Y(s)=0

Solving for Y(s) we get

\large\bf s^2Y(s)-4s-2-6(sY(s)-4)+9Y(s)=0\Rightarrow (s^2-6s+9)Y(s)-4s+22=0\Rightarrow\\\\\Rightarrow Y(s)=\frac{4s-22}{s^2-6s+9}

Now, we brake down the rational expression of Y(s) into partial fractions

\large\bf \frac{4s-22}{s^2-6s+9}=\frac{4s-22}{(s-3)^2}=\frac{A}{s-3}+\frac{B}{(s-3)^2}

The numerator of the addition at the right must be equal to 4s-22, so

A(s - 3) + B = 4s - 22

As - 3A + B = 4s - 22

we deduct from here  

A = 4 and -3A + B = -22, so

A = 4 and B = -22 + 12 = -10

It means that

\large\bf \frac{4s-22}{s^2-6s+9}=\frac{4}{s-3}-\frac{10}{(s-3)^2}

and

\large\bf Y(s)=\frac{4}{s-3}-\frac{10}{(s-3)^2}

By taking the inverse Laplace transform on both sides and using the linearity of the inverse:

\large\bf y(t)=L^{-1}\left\{Y(s)\right\}=4L^{-1}\left\{\frac{1}{s-3}\right\}-10L^{-1}\left\{\frac{1}{(s-3)^2}\right\}

we know that

\large\bf L^{-1}\left\{\frac{1}{s-3}\right\}=e^{3t}

and for the first translation property of the inverse Laplace transform

\large\bf L^{-1}\left\{\frac{1}{(s-3)^2}\right\}=e^{3t}L^{-1}\left\{\frac{1}{s^2}\right\}=e^{3t}t=te^{3t}

and the solution of our differential equation is

\large\bf y(t)=L^{-1}\left\{Y(s)\right\}=4L^{-1}\left\{\frac{1}{s-3}\right\}-10L^{-1}\left\{\frac{1}{(s-3)^2}\right\}=\\\\4e^{3t}-10te^{3t}=2e^{3t}(2-5t)\\\\\boxed{y(t)=2e^{3t}(2-5t)}

5 0
3 years ago
Two lengths of a triangle are shown.
Solnce55 [7]

Answer:

11 ft

Step-by-step explanation:

Given the two lengths of a triangle as

AB = 6ft

AC = 6ft

This is an isosceles triangle because only 2 sides are equal.

In an isosceles triangle, the sum of 2 (sides) lengths must be greater than the other length.

Therefore, let's assume the following:

i) AC + AB > BC

6 + 6 > BC

12 > BC (BC is less than 12)

BC < 12

ii) BC + AC > AB

BC + 6 > 6

BC > 6 - 6

BC > 0

Therefore the range of values for BC =

0 < BC < 12

Since BC must be bigger than one of the lengths and it must also be less than the sum of the 2 sides. The length of BC could be 11 because it is less than (6+6) 12 and greater than 6.

5 0
2 years ago
If you vertically stretch the exponential function f(x)=2^x by a factor of 3, what is the equation of the new function
AleksAgata [21]

Answer:

y=3*2^{x}

Step-by-step explanation:

A vertical stretch of a function means the output values have changed by a factor of 3 or multiplication by 3. Recall, an exponential function has the basic form

y=ab^{2}.

If our equation is f(x)=2^x, then a=1. To stretch it vertically by a factor of 3, we multiply a by 3. So 1(3)=3. The value of a now becomes 3.

y=3*2^{x}


7 0
3 years ago
Other questions:
  • Mr. Conners put a fence around the outside of his rectangular yard shown at the right. He put a fence post every 6 feet. How man
    8·2 answers
  • Help will make right person brainly
    12·2 answers
  • The two histograms below show the weights of dogs at two different veterinarian offices.
    13·1 answer
  • Line s is shown. Two points on a parallel line t are (−2,−6) and (z+2,z). Solve for z
    14·1 answer
  • Please answer the attached question by selecting of the the given answers.
    5·1 answer
  • What is the slope of the linear function that passes through the points (9, -2) and (-4,-6)?
    14·1 answer
  • Helpppppp please ASAPpppppppppppppp!!!!!!!!!!!!!!!!!!
    14·1 answer
  • 3/4 + (1/3 ÷ 1/6)-(-1/2)=
    13·1 answer
  • Sin2A-sin2B+sin2C=4cosA×sinB×cosC<br>​
    10·1 answer
  • A survey was given to 323 people asking whether people like dogs and/or cats.
    9·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!