All categories

3 years ago

Find AC. PLSSS HELP BRAINLIEST....

Mathematics

2 answers:

Kamila [148]3 years ago

6 0

Answer:

AC ≈ 5.3 ( to the nearest tenth )

Step-by-step explanation:

Using the cosine ratio in the right triangle.

cos68° = $\frac{adjacent}{hypotenuse}$ = $\frac{AB}{AC}$ = $\frac{2}{AC}$

Multiply both sides by AC

AC × cos68° = 2 ( divide both sides by cos68° )

AC = $\frac{2}{cos68}$ ≈ 5.3

MrRissso [65]3 years ago

4 0

Answer:

5.3

Step-by-step explanation:

Cos(68) = adjacent/hypotenuse

Cos(68) = 2/AC

AC = 2/cos(68)

AC = 5.3389343253

AC = 5.3

You might be interested in

Three security cameras were mounted at the corners of a triangles parking lot. Camera 1 was 110 ft from camera 2, which was 137

Nata [24]

Answer:

<em>Camera 2nd has to cover the maximum angle, i.e. </em> $78.70^\circ$ .

Step-by-step explanation:

Please have a look at the triangular park represented as a triangle $\triangle ABC$ with sides

a = 110 ft

b = 158 ft

c = 137 ft

1st camera is located at point C, 2nd camera at point B and 3rd camera at point A respectively.

We can use law of cosines here, to find out the angles $\angle A, \angle B, \angle C$

As per Law of cosine:

$cos C = \dfrac{a^{2}+b^2-c^2 }{2ab}\\cos B = \dfrac{a^{2}+c^2-b^2 }{2ac}\\cos A = \dfrac{b^{2}+c^2-a^2 }{2bc}$

Putting the values of a,b and c to find out angles $\angle A, \angle B, \angle C$ .

$cos C = \dfrac{110^{2}+158^2-137^2 }{2\times 110 \times 158}\\\Rightarrow cos C = \dfrac{12100+24964-18769 }{24760}\\\Rightarrow cos C =0.526\\\Rightarrow C = 58.24^\circ$

$cos B = \dfrac{110^{2}+137^2-158^2 }{2\times 110 \times 137}\\\Rightarrow cos B = \dfrac{12100+18769 -24964}{30140}\\\Rightarrow cos B = \dfrac{5905}{30140}\\\Rightarrow cos B =0.196\\\Rightarrow B = 78.70^\circ$

$cos A = \dfrac{158^{2}+137^2-110^2 }{2\times 158 \times 137}\\\Rightarrow cos A = \dfrac{24964+18769-12100}{43292}\\\Rightarrow cos A = \dfrac{31633}{43292}\\\Rightarrow cos A = 0.731\\\Rightarrow A = 43.05^\circ$

<em>Camera 2nd has to cover the maximum angle</em>, i.e. $78.70^\circ$ .

6 0

3 years ago

Can someone nice enough help me ASAP this is 5th Grade Math!

iren [92.7K]

Hello from MrBillDoesMath!

Answer:

"He plans to sell the carrots for $5 per bunch..." is not needed

Discussion:

The question asked is "About how many bunches will the farmer make? The text "He plans to sell the carrots for $5 per bunch..." is not needed as it does not relate to the question asked.

Regards,

MrB

4 0

3 years ago

Read 2 more answers

PLEASE GET THE FILL IN BLANK ANSWER RIGHT ixl pLEASE

jolli1 [7]

Required equation in slope intercept form is: $y=5x+4$

Step-by-step explanation:

Given

Let m denote the slope of line

m = 5

the line passes though (1,9)

Slope-intercept form of equation of line is:

$y= mx+b$

Putting m=5 in the equation

$y = 5x+b$

Putting (1,9) in the equation

$9 = 5(1) +b\\9 = 5+b\\b = 9-5\\b = 4$

Putting the value of b

$y = 5x+4$

Hence,

Required equation in slope intercept form is: $y=5x+4$

Keywords: Equation, linear equation

Learn more about equation of line at:

#LearnwithBrainly

3 0

3 years ago

In a cafeteria 3/10 of the students are eating salads, and 3/5 are eating sandwiches. There are 20 students in the cafeteria. Ho

Elanso [62]

We know that 3/10*20=6 students are eating salads.

We also know that 3/5*20=12 students are eating sandwiches.

Assuming each person only eats one thing, there are 20-12-6=2 students eating lunches other than salads or sandwiches.

8 0

3 years ago

How to solve <img src="https://tex.z-dn.net/?f=log_%7By%7D%285y%29%20%3D%202" id="TexFormula1" title="log_{y}(5y) = 2" alt="log_

Natalija [7]

Answer:

y = 5

Step-by-step explanation:

Expand the logarithm:

$\log_y{(5)}+\log_y{(y)}=2\\\\\dfrac{\log{(5)}}{\log{(y)}}+1=2 \quad\text{change of base formula}\\\\\dfrac{\log{(5)}}{\log{(y)}}=1 \quad\text{subtract 1}\\\\\log{(5)}=\log{(y)} \quad\text{multiply by log(y)}\\\\5=y \quad\text{take the anti-log}$

_____

You can also take the antilog first:

5y = y²

y(y -5) = 0 . . . . . subtract 5y, factor

y = 0 or 5 . . . . . y=0 is not a viable solution, so y=5.

5 0

4 years ago