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4 years ago

Which statement about kites is false ?

Mathematics

1 answer:

Strike441 [17]4 years ago

8 0

The worng answer is [b]
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See the picture below

mart [117]

Answer:

a) 301.59 cubic centimeters

b) 235.87 square centimeters

Step-by-step explanation:

Volume of ice cream cone is volume of hemisphere PLUS volume of cone.

Volume of Hemisphere = $\frac{\frac{4}{3}\pi r^3}{2}$

radius is given as 4, so,

Volume of Hemisphere = $\frac{\frac{4}{3}\pi r^3}{2}\\=\frac{\frac{4}{3}\pi (4)^3}{2}\\=134.04$

Now, Volume of Cone = $\frac{1}{3}\pi r^2 h$

Where radius is 4 and height is 10, so,

Volume of Cone = $\frac{1}{3}\pi r^2 h\\=\frac{1}{3}\pi (4)^2 (10)\\=167.55$

Volume of Ice Cream Cone = 134.04 + 167.55 = 301.59 cubic centimeters

Surface area of ice cream cone is surface area of hemisphere PLUS surface area of cone.

Surface Area of Hemisphere = $2\pi r^2\\=2\pi (4)^2\\=100.53$

Surface Area of Cone = $\pi r^2+\pi rl$

We dont need to use the first part, $\pi r^2$ since it is "inside". We need to find l, slant height, by using pythagorean theorem on a triangle we can make (bottom right).

4^2 + 10^ 2 = l^2

16 + 100 = l^2

116 = l^2

l = 10.77

Now to find the surface area of cone = $\pi rl\\=\pi (4)(10.77)\\=135.34$

Surface area of ice cream cone = 100.53 + 135.34 = 235.87 square centimeters

5 0

3 years ago

The quotient of 36 and 3 is j. write expression

Dovator [93]

This might be a mistake but i'll give it a go:

36/3 = j

4 0

3 years ago

Read 2 more answers

C is the same as the total of 257 and q write equation (IXL)

vampirchik [111]

The equation would be c = 257 + q

5 0

3 years ago

Which is the net for this triangular prism?

pishuonlain [190]

Bottom right corner would be the correct answer

8 0

2 years ago

Given the sample 4, −2, −6, 19, 6, add one more sample value that will neither change the mean nor the variance. Round to two de

DedPeter [7]

Answer:

Cannot create sample

Step-by-step explanation:

We are given the following in the question:

4, -2, -6, 19, 6

Formula:

$\text{Variance} = \displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}$

where $x_i$ are data points, $\bar{x}$ is the mean and n is the number of observations.

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

$Mean =\displaystyle\frac{21}{5} = 4.2$

Sum of squares of differences = 0.04 + 38.44 + 104.04 + 219.04 + 3.24 = 364.8

$s^2 = \dfrac{364.8}{4}} = 91.2$

If we add an observation equal to the mean of given sample, then the mean and of new sample will not change.

New sample:

4, -2, -6, 19, 6, 4.2

$Mean =\displaystyle\frac{25.2}{6} = 4.2$

Sum of squares of differences = 0.04 + 38.44 + 104.04 + 219.04 + 3.24 + 0 = 364.8

$s^2 = \dfrac{364.8}{5}} = 72.96$

Thus, the variance of new sample changes.

Thus, it is not possible to create a sample.

5 0

3 years ago