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Genrish500 [490]
3 years ago
15

Which statement about kites is false ?

Mathematics
1 answer:
Strike441 [17]3 years ago
8 0
The worng answer is [b] 
hope this helps you 
have a great day
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I need help with another set of math questions.
Anit [1.1K]
For question 11, you essentially need to find when h(t) = 0, since that is when the height of the ball reaches 0 (ie touches the ground).

For question 12, it is asking for a maximum height, so you need to find when dh/dt = 0 and taking the second derivative to prove that there is maximum at t. That will find you the time at which the ball will hit a maximum height.

Rinse and repeat question 12 for question 13
7 0
2 years ago
Please help. I don't need a big explanation just a answer
stiv31 [10]
A answer of the explanation for the explanation is the answer
6 0
3 years ago
suppose Richard walks one kilometer every 10 minutes how many meters are there can you walk in an hour at this new rate
Ipatiy [6.2K]
One kilometer is 1000 meters.  One hour is 60 minutes, or six segments of 10 minutes each.  If you can walk 1000 meters in 10 minutes, you can walk 6000 in an hour (that is REALLY fast, by the way)
3 0
3 years ago
Let z = 5. What is the value of (10 + 25) ÷ z?
Murrr4er [49]

Answer:

<h2>A. 7</h2>

Step-by-step explanation:

Put z = 5 to the expression (10 + 25) ÷ z:

(10 + 25) ÷ 5 = 35 ÷ 5 = 7

5 0
3 years ago
A manufacturer is planning to sell a new product at the price of 210 dollars per unit and estimates that if x thousand dollars i
sattari [20]

Answer:

Development costs: $2757

Promotion costs: $3155

Step-by-step explanation:

This might seem like a two-variable problem, but in actuality it's not - because the demand function is a sum of two components, each being independent and using only one variable, we can solve for the two separately.

Moreover, the price per unit and cost per unit is constant, so each product yields exactly $80 ($210 - $130).

Let's solve separately.

We need to maximize:

$80 * 160y/(y+4) - 1000y = $12800 * y/(y+4) - $1000*y

$80 * 170x/(x+7) - 1000x = $13600 * x/(x+7) - $1000*x

Let's go:

$12800 * y/(y+4) - $1000*y = $12800 * (1 - 4/(y+4)) - $1000y = $12800 - $51200/(y+4) - $1000*y

we analyze the derivative. $12800 is a constant, so we can skip it. Derivative of 1/(y+4) is -(y+4)^-2, derivative of $1000y is $1000.

deriv = $51200/(y+4)/(y+4) - $1000

We find the changepoints by analyzing $51200/(y+4)/(y+4) - $1000 = $0. We don't need to worry about y+4 = 0 because we cannot spend negative money on development/advertisement.

(y+4)^2 = $51.2

y+4 ~= 7.155417528 (or -y-4 = 7.1554... but it doesn't make sense because negative budget so we don't analyze).

y ~= 3.155417528

lastly, we should check that it's actually a maximum there - but it is, the original function goes to negative infinity.

rounding $1000y to the nearest dollar gives us $3155

Let's do the same for x:

$13600 * x/(x+7) - $1000*x = $13600 * (1 - 7/(x+7)) - $1000x = $13600 - $95200/(x+7) - $1000*x

deriv = $95200/(x+7)/(x+7) - $1000

$95200/(x+7)/(x+7) - $1000 = $0

(x+7)^2 = 95.2

(x+7) ~= 9.75704873412

x ~= 2.75704...

rounding $1000x to the nearest dollar yields $2757

3 0
2 years ago
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