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eduard
3 years ago
13

Exercise 30 please , show work

Mathematics
2 answers:
mezya [45]3 years ago
6 0
-8(2a-3b)-5(6b-4a)=\\
-16a+24b-30b+20a=\\
4a-6b
ArbitrLikvidat [17]3 years ago
3 0
-8(2a-3b)-5(6b-4a)=\\=-8 \times 2a -8 \times (-3b)-5 \times 6b-5 \times (-4a)= \\
=-16a+24b-30b+20a= \\
=20a-16a+24b-30b= \\
=(20-16)a+(24-30)b= \\
=4a-6b
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Answer

B      Janae types 30 words each minute.

Step-by-step explanation:

4 0
3 years ago
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A family buys 5 airline tickets online. The family buys travel insurance that costs ​$17 per ticket. The total cost is ​$890. Le
timurjin [86]

Answer:  Equation that represents this situation is 5(x+17) = 1495,

Price of one ticket is 282

Step-by-step explanation:

Here x represents the price of one ticket,

Also, a person bought travel insurance that costs $17 per ticket.

Hence, the total cost of a person = x + 17

⇒ The total cost of 5 person = 5 ( x + 17 )

But, According to the question,

5 ( x + 17 ) = 1495

⇒ x + 17 = 299

⇒ x = 299 - 17

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Hence, the price of one ticket = $ 282

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3 years ago
Hailey paid $13 for 1 3/7 kg of sliced salami <br><br> What was the cost per kilogram of salami
JulijaS [17]

Translate words into numbers.

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Then, note that division is the same as multiplying by the divisor's reciprocal.

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4 0
3 years ago
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What is the correct answer NEED ANSWER ASAP​
Llana [10]

Answer:

Your answer is

x-int: (3 , 0) ,  (-3/2 , 0)

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Step-by-step explanation:

4 0
2 years ago
if the recommended daily allowance for vitamin c is 60 mg per day and there are 70 mg of vitamin C per 100 g orange, how many 3.
noname [10]

Answer: 7

Step-by-step explanation:

Given : The recommended daily allowance for vitamin c is 60 mg per day .

Then, for one whole week , the recommended allowance for vitamin c will be :-

7\times60=420\text{ mg}

Also, there are 70 mg of vitamin C per 100 g orange.

1 g = 1000 ml

The proportion of Vitamin C in 100 g = \dfrac{70}{100000}=0.0007

1 oz =28.3495 grams

Then, 3\ oz= 3\times28.3495=85.0485 \text{ gm}=85048.5\ mg

Then, amount of vitamin C in 85048.5 mg = 0.0007\times85048.5=59.53395\approx59.53\ mg

Then, the number of oranges have to eat each week to meet this requirement= \dfrac{420}{59.53}\approx7

Hence,  about 7 oranges you would have to eat each week to meet this requirement.

8 0
3 years ago
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