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eduard
4 years ago
13

Exercise 30 please , show work

Mathematics
2 answers:
mezya [45]4 years ago
6 0
-8(2a-3b)-5(6b-4a)=\\
-16a+24b-30b+20a=\\
4a-6b
ArbitrLikvidat [17]4 years ago
3 0
-8(2a-3b)-5(6b-4a)=\\=-8 \times 2a -8 \times (-3b)-5 \times 6b-5 \times (-4a)= \\
=-16a+24b-30b+20a= \\
=20a-16a+24b-30b= \\
=(20-16)a+(24-30)b= \\
=4a-6b
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To find:

The smallest possible value of K.

Solution:

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(x+s)(x-t)=x^2+Kx-40

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K is a positive integer if s>t.

And

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The factor pairs of 40 are (1,40), (2,20), (4,10), (5,8), (8,5), (10,4), (20,2) and (40,1).

Since s>t, therefore the possible values for (s,t) are (8,5), (10,4), (20,2) and (40,1).

Using (i), find the value of K for each factor pair.

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Therefore, the smallest possible value of K is 3.

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Answer:

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Step-by-step explanation:

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