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eduard
3 years ago
13

Exercise 30 please , show work

Mathematics
2 answers:
mezya [45]3 years ago
6 0
-8(2a-3b)-5(6b-4a)=\\
-16a+24b-30b+20a=\\
4a-6b
ArbitrLikvidat [17]3 years ago
3 0
-8(2a-3b)-5(6b-4a)=\\=-8 \times 2a -8 \times (-3b)-5 \times 6b-5 \times (-4a)= \\
=-16a+24b-30b+20a= \\
=20a-16a+24b-30b= \\
=(20-16)a+(24-30)b= \\
=4a-6b
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3 years ago
You have researched your dream around-the-world vacation and determined that the total cost of the vacation will be $39,000. You
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Answer:

41.8 years

Step-by-step explanation:

From

A = P(1+r/n)^{nt}

A= 39000

r = 10.5%

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t = the unknown

t= [ ln(A) - ln(P) ] / n[ln(1 + r/n)]

t= ln 39000 - ln 485/ 12[ln(1+0.105/12)]

t= 10.57 - 6.18/0.105

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4 years ago
Describe the effect an increase in n, the number of payment periods, has on the monthly payment P in the formula 2007-11-02-00-0
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8 0
3 years ago
Read 2 more answers
If n is a positive integer, how many 5-tuples of integers from 1 through n can be formed in which the elements of the 5-tuple ar
sleet_krkn [62]

This question is incomplete, the complete question is;

If n is a positive integer, how many 5-tuples of integers from 1 through n can be formed in which the elements of the 5-tuple are written in increasing order but are not necessarily distinct.

In other words, how many 5-tuples of integers  ( h, i , j , m ), are there with  n ≥ h ≥ i ≥ j ≥ k ≥ m ≥ 1 ?

Answer:

the number of 5-tuples of integers from 1 through n that can be formed is [ n( n+1 ) ( n+2 ) ( n+3 ) ( n+4 ) ] / 120

Step-by-step explanation:

Given the data in the question;

Any quintuple ( h, i , j , m ), with n ≥ h ≥ i ≥ j ≥ k ≥ m ≥ 1

this can be represented as a string of ( n-1 ) vertical bars and 5 crosses.

So the positions of the crosses will indicate which 5 integers from 1 to n are indicated in the n-tuple'

Hence, the number of such quintuple is the same as the number of strings of ( n-1 ) vertical bars and 5 crosses such as;

\left[\begin{array}{ccccc}5&+&n&-&1\\&&5\\\end{array}\right] = \left[\begin{array}{ccc}n&+&4\\&5&\\\end{array}\right]

= [( n + 4 )! ] / [ 5!( n + 4 - 5 )! ]

= [( n + 4 )!] / [ 5!( n-1 )! ]

= [ n( n+1 ) ( n+2 ) ( n+3 ) ( n+4 ) ] / 120

Therefore, the number of 5-tuples of integers from 1 through n that can be formed is [ n( n+1 ) ( n+2 ) ( n+3 ) ( n+4 ) ] / 120

4 0
3 years ago
The table shows how many males and females attended two different movies. How would you find the joint relative frequency of bei
kirza4 [7]

Answer:

B. Divide 124 by 229.

Step-by-step explanation:

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So, to find the joint relative frequency of being male and attending a drama movie, you should divide 124 by 229.

8 0
3 years ago
Read 2 more answers
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