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3 years ago

7

Austen has $20 in a savings account that earns 5% annually. The interest is not

1 answer:

marta [7]3 years ago

3 0

20x(5/100)=1

That is the interest after one year

Add to the principal:20+1=21

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What’s 23-(+25)-(-7)

Tamiku [17]

Answer: It =5

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3 years ago

Vector v is plotted below. What is the length of the x-component of v?

Rzqust [24]

Answer:

C. 1

Step-by-step explanation:

We can see that each box in the grid is one unit.

We count one box to the right on the horizontal axis and 4 boxes down on the vertical axes to obtain the components of vector v.

See graph in attachment.

Therefore the components of vector v is

$\binom{1}{-4}$ .

The length of the x component is 1 unit

Hence the correct answer is C.

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3 years ago

A. what's 7 X 8?<br> B. what's 9 X 8?<br> C. what's 8 X 8?

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Answer:

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Step-by-step explanation:

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3 years ago

There are 10,000 citizens in baconburg. each year, the population increases by 25%. write an exponential function to model this

vodomira [7]

Answer:

Step-by-step explanation:

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3 years ago

In Exercises 5-7, find all the exact t-values for which the given statement is true,

bearhunter [10]

Answer: See Below

<u>Step-by-step explanation:</u>

NOTE: You need the Unit Circle to answer these (attached)

5) cos (t) = 1

Where on the Unit Circle does cos = 1?

Answer: at 0π (0°) and all rotations of 2π (360°)

In radians: t = 0π + 2πn

In degrees: t = 0° + 360n

******************************************************************************

$6)\quad sin (t) = \dfrac{1}{2}$

Where on the Unit Circle does $sin = \dfrac{1}{2}$

<em>Hint: sin is only positive in Quadrants I and II</em>

$\text{Answer: at}\ \dfrac{\pi}{6}\ (30^o)\ \text{and at}\ \dfrac{5\pi}{6}\ (150^o)\ \text{and all rotations of}\ 2\pi \ (360^o)$

$\text{In radians:}\ t = \dfrac{\pi}{6} + 2\pi n \quad \text{and}\quad \dfrac{5\pi}{6} + 2\pi n$

In degrees: t = 30° + 360n and 150° + 360n

******************************************************************************

$7)\quad tan (t) = -\sqrt3$

Where on the Unit Circle does $\dfrac{sin}{cos} = \dfrac{-\sqrt3}{1}\ or\ \dfrac{\sqrt3}{-1}\quad \rightarrow \quad (1,-\sqrt3)\ or\ (-1, \sqrt3)$

<em>Hint: sin and cos are only opposite signs in Quadrants II and IV</em>

$\text{Answer: at}\ \dfrac{2\pi}{3}\ (120^o)\ \text{and at}\ \dfrac{5\pi}{3}\ (300^o)\ \text{and all rotations of}\ 2\pi \ (360^o)$

$\text{In radians:}\ t = \dfrac{2\pi}{3} + 2\pi n \quad \text{and}\quad \dfrac{5\pi}{3} + 2\pi n$

In degrees: t = 120° + 360n and 300° + 360n

4 0

3 years ago