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DIA [1.3K]
3 years ago
14

Solutions of x^5-32i=0 in rectangular form.

Mathematics
1 answer:
elixir [45]3 years ago
6 0
\bf i^5\implies  i^4i\implies 1i\implies i
\\\\\\
32=2^5\\\\
-------------------------------\\\\
x^5-32i=0\implies x^5=32i\implies x=\sqrt[5]{32i}\implies x=\sqrt[5]{2^5i^5}
\\\\\\
x=\sqrt[5]{(2i)^5}\implies x=2i\implies x=0+2i\implies (0~,~2)
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