Question

Solutions of x^5-32i=0 in rectangular form.

Answer 1

$\bf i^5\implies i^4i\implies 1i\implies i \\\\\\ 32=2^5\\\\ -------------------------------\\\\ x^5-32i=0\implies x^5=32i\implies x=\sqrt[5]{32i}\implies x=\sqrt[5]{2^5i^5} \\\\\\ x=\sqrt[5]{(2i)^5}\implies x=2i\implies x=0+2i\implies (0~,~2)$