Answer:
The confidence interval for the true mean calorie content is
Step-by-step explanation:
In this problem we know the mean and standard deviation fo the sample, so we can compute the CI like this:
We need to determine t for 10-1=9 degrees of freedom and 99% confidence level. We look up in the t-table and the value for t is 3.2498.
Then we can calculate the limits of the CI:
Answer: 17/2
Step-by-step explanation:
1- <u>Add</u> up the numbers.
2- Cut 2 below the second fraction with 2 cubed, then 2 will be squared.
3- Solve the potentiation (2 squared is equal to four, because 2 * 2 = 4)
4- And, finally, compute 9/2 + 4. It will give 17/2.
Take 6.5 divided by 2.75 which equals 2.36, 2.36 times 2.75 equals 6.5
the correct answer is B. y-intercept = 4 and slope = -2
the y intercept is just where the line crosses the y axis and you can clearly see that happens at +4
The slope = Rise/run which in this case = -2
Answer: the t-test statistic is - 1.77
Step-by-step explanation:
For the null hypothesis,
H 0: μ = 2600
For the alternative hypothesis,
H a: μ ≠ 2600
This is a two tailed test
Since no population standard deviation is given, the distribution is a student's t.
Since n = 50,
Degrees of freedom, df = n - 1 = 50 - 1 = 49
t = (x - µ)/(s/√n)
Where
x = sample mean = $2450
µ = population mean = $2600
s = samples standard deviation = $600
Therefore,
t = (2450 - 2600)/(600/√50) = - 1.77
