Wouldn’t the faces be the triangle parts ? Like p,q,o p,m,q n,o,q
I believe you are referring to the half-life formula, which is used to calculate the half-life (when the substance drops to half of its original amount) of radioactive substances. The equation is as follows:

<em>A</em> is the remaining amount
<em>P</em> is the initial amount
<em>t</em> is the time that has passed
<em>h</em> is the half-life of the substance
When plugging values into the equation, make sure that <em>t </em>and <em>h </em>are both measured in the same unit (e.g. <em>t </em>days and <em>h </em>days), as well as <em>A </em>and <em>P</em>.
If the roots to such a polynomial are 2 and

, then we can write it as

courtesy of the fundamental theorem of algebra. Now expanding yields

which would be the correct answer, but clearly this option is not listed. Which is silly, because none of the offered solutions are *the* polynomial of lowest degree and leading coefficient 1.
So this makes me think you're expected to increase the multiplicity of one of the given roots, or you're expected to pull another root out of thin air. Judging by the choices, I think it's the latter, and that you're somehow supposed to know to use

as a root. In this case, that would make our polynomial

so that the answer is (probably) the third choice.
Whoever originally wrote this question should reevaluate their word choice...
There are 10 portions to the circle, and 7 of the 10 are shaded. 7/10 is 70%
Answer:
1) 288 cans
2) about 41 cans per team
Step-by-step explanation:
For number one you would multiply the numbers
24x12=288
there are 288 cans in total
2) divide 288 by 7 to distribute the cans evenly
each team gets about 41 cans