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2 years ago

What is this as a slope?

Mathematics

1 answer:

Fofino [41]2 years ago

8 0

Answer:

5/4

Step-by-step explanation:

Using coordinates (10,0) and (90,100)

Slope m = (y2-y1)/(x2-x1)

m = (100 - 0)/(90 - 10) = 100/80 = 10/8 = 5/4

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Note: Enter your answer and show all the steps that you use to solve this problem in the space provided. f ( x ) = 9 x 3 + 2 x 2

sladkih [1.3K]

Answer:

2x(2x²+x+1)

Dtep-by-step explanation:

f(x) = 9x³+2x²-5x+4

g(x) = 5x³-7x+4

f(x) - g(x)

= 9x³+2x²-5x+4 - (5x³-7x+4)

= 9x³+2x²-5x+4-5x³+7x-5

= 4x³+2x²+2x

= 2x(2x²+x+1)

3 0

3 years ago

If the focal point is (2,5) and the directrix is y = -7. Find the equation of the parabola.

mihalych1998 [28]

Answer:

The equation of the parabola is (x-2)^2 = 48(y-5)

Step-by-step explanation:

Mathematically, we can obtain the equation of a parabola from its focal point and the directrix given.

Firstly, we need to find the distance between the director and the vertex

That would be ;

|-7-(5)| = 12

We should kindly note that the directrix is below the vertex and thus it is a right-side parabola with a positive value of p = 12

Thus, the equation needed would be;

(x-h)^2 = 4p(y-k)

From the question, h = 2

p = 12 ( calculated) and k = 5

So the equation would be;

(x-2)^2 = 4(12)(y-5)

= (x-2)^2 = 48(y-5)

8 0

4 years ago

APEX HELP PLEASE

Ivenika [448]

The answer to the question is d

4 0

3 years ago

Computing growth rates (I): Suppose Xt=(1.04)^t and Yt=(1.02)^tCalculate the growth rate of Zt in each of the following cases:(a

Doss [256]

Answer:

$z(t) = (0.9808)^t$

$z(t) = (1.0196)^t$

$z(t) = (0.9808)^t$

$z(t) = (1.03)^t$

$z(t) = (1.0404)^t$

$z(t) = (1.0001)^t$

Step-by-step explanation:

We are given the following in the question:

$x(t)=(1.04)^t\\y(t)t=(1.02)^t$

We have to find the growth rate z(t) in each of the following cases:

(a) z = xy

$z(t) = x(t)y(t)\\z(t) = (1.04)^t.(1.02)^t\\z(t) = (1.04\times 1.02)^t\\z(t) = (1.0608)^t$

(b) z=x/y

$z(t) =\displaystyle\frac{x(t)}{y(t)}\\\\z(t) = \frac{(1.04)^t}{(1.02)^t} = \bigg(\frac{1.04}{1.02}\bigg)^t\\\\z(t) = (1.0196)^t$

(c) z=y/x

$z(t) =\displaystyle\frac{y(t)}{x(t)}\\\\z(t) = \frac{(1.02)^t}{(1.04)^t} = \bigg(\frac{1.02}{1.04}\bigg)^t\\\\z(t) = (0.9808)^t$

(d) z=x^(1/2) y^(1/2)

$z(t) = (x(t))^{\frac{1}{2}}(y(t))^{\frac{1}{2}}\\z(t) = ((1.04)^t)^\frac{1}{2} ((1.02)^t)^\frac{1}{2}\\z(t) = (1.0608)^{\frac{t}{2}}\\z(t) = (1.03)^t$

(e) z=(x/y)^2

$z(t) =\bigg(\displaystyle\frac{x(t)}{y(t)}\bigg)^2\\\\z(t) =\bigg( \frac{(1.04)^t}{(1.02)^t}\bigg)^2 = \bigg(\frac{1.04}{1.02}\bigg)^{2t}\\\\z(t) = (1.0404)^t$

(f) z=x^(-1/3)y^(2/3)

$z(t) = (x(t))^{\frac{-1}{3}}(y(t))^{\frac{2}{3}}\\z(t) = ((1.04)^t)^{\frac{-1}{3}}((1.02)^t)^{\frac{2}{3}}\\z(t) = ((1.04)^{\frac{-1}{3}})^t((1.02)^{\frac{2}{3}})^t\\z(t) = (1.04^{\frac{-1}{3}}\times 1.02^{\frac{2}{3}})^t\\z(t) = (1.0001)^t$

5 0

3 years ago

Simplify the expression.<br> 6x - 7x

Lubov Fominskaja [6]

Answer:

-x

Step-by-step explanation:

6 0

4 years ago

Read 2 more answers