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3 years ago

Please help solve

Mathematics

1 answer:

Veronika [31]3 years ago

3 0

The answers to the first two systems of equations

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Find the slope of the line that passes through (41, 81) and (75, 71).

labwork [276]

Answer:

y=5/17x+17 3/17

Step-by-step explanation:

put the points on slope to get 5/17. then use point slope form (y-y1)=m(x-x1) and plug in 41 for x1, 81 for y1, and 5/17x for m

8 0

3 years ago

PLEASE HELP FAST triangle abc is translated 4 units down and 6 units right, resulting in triangle A’B’C’

Lina20 [59]

Answer:

D. (6,-1)

Step-by-step explanation:

Translating is just sliding slide the point B down 4 units from where it is and then move over 6 units to the right.

6 0

3 years ago

In this problem we consider an equation in differential form Mdx+Ndy=0. (4x+2y)dx+(2x+8y)dy=0 Find My= 2 Nx= 2 If the problem is

zheka24 [161]

Answer:

$f(x,y)=2x^2+4y^2+2xy=C_1\\\\Where\\\\y(x)=\frac{1}{4} (-x\pm \sqrt{-7x^2+C_1} )$

Step-by-step explanation:

Let:

$M(x,y)=4x+2y\\\\and\\\\N(x,y)=2x+8y$

This is and exact equation, because:

$\frac{\partial M(x,y)}{\partial y} =2=\frac{\partial N}{\partial x}$

So, define f(x,y) such that:

$\frac{\partial f(x,y)}{\partial x} =M(x,y)\\\\and\\\\\frac{\partial f(x,y)}{\partial y} =N(x,y)$

The solution will be given by:

$f(x,y)=C_1$

Where C1 is an arbitrary constant

Integrate $\frac{\partial f(x,y)}{\partial x}$ with respect to x in order to find f(x,y):

$f(x,y)=\int\ {4x+2y} \, dx =2x^2+2xy+g(y)$

Where g(y) is an arbitrary function of y.

Differentiate f(x,y) with respect to y in order to find g(y):

$\frac{\partial f(x,y)}{\partial y} =2x+\frac{d g(y)}{dy}$

Substitute into $\frac{\partial f(x,y)}{\partial y} =N(x,y)$

$2x+\frac{dg(y)}{dy} =2x+8y\\\\Solve\hspace{3}for\hspace{3}\frac{dg(y)}{dy}\\\\\frac{dg(y)}{dy}=8y$

Integrate $\frac{dg(y)}{dy}$ with respect to y:

$g(y)=\int\ {8y} \, dy =4y^2$

Substitute g(y) into f(x,y):

$f(x,y)=2x^2+4y^2+2xy$

The solution is f(x,y)=C1

$f(x,y)=2x^2+4y^2+2xy=C_1$

Solving y using quadratic formula:

$y(x)=\frac{1}{4} (-x\pm \sqrt{-7x^2+C_1} )$

4 0

3 years ago

What is (-12) / 6 + 2

Nata [24]

-12/6+2
=-12/6+2/1
=-2/1+2/1
=-2+2/1
=0

From looking at that equation you put this is my solution.

7 0

3 years ago

Read 2 more answers

In the triangle below, the value of h is 3/4 the side length that is labeled on the figure. What is the area of the triangle?

Nataly_w [17]

The correct answer is: [C]: " 8.64 mm² " .
________________________________________________
Note:
______________________________________________________
Area of a triangle = (½)*(base length)*(height; that is, "perpendicular height");
________________________________________________________
or: A = (½) * b * h ;
_________________________
Given: "b = 4.8 mm" ;
            "h = (¾) * b = (¾)* (4.8 mm) = 3.6 mm ;
               → h = 3.6 mm ;
_____________________________________
→ A = (½) * b * h ;

           = (½) * (4.8 mm) * (3.6 mm) ;

    → A = 8.64 mm² ; which is: Answer choice: [C] .
______________________________________

4 0

3 years ago