To factor quadratic equations of the form ax^2+bx+c=y, you must find two values, j and k, which satisfy two conditions.
jk=ac and j+k=b
The you replace the single linear term bx with jx and kx. Finally then you factor the first pair of terms and the second pair of terms. In this problem...
2k^2-5k-18=0
2k^2+4k-9k-18=0
2k(k+2)-9(k+2)=0
(2k-9)(k+2)=0
so k=-2 and 9/2
k=(-2, 4.5)
Answer:
5/9
Step-by-step explanation:
Let the denominator be x and numerator be y.
Given, numerator is 4 less than denominator
=> y = x - 4 ...(1)
When 5 is added to both:
Numerator = y + 5 , and, denominator = x + 5
Now their ratio is 5/7.
=> (y + 5)/(x + 5) = 5/7
=> 7(y + 5) = 5(x + 5)
=> 7y + 35 = 5x + 25
=> 7y - 5x = 25 - 35
=> 7(x - 4) - 5x = -10 {y=x-4}
=> 7x - 28 - 5x = -10
=> 2x = 18
=> x = 9
Thus,
Fraction is y/x = (x-4)/x = (9-4)/9 = 5/9
Answer:
The Answer is 64 and I got that by doing 6.4 × 10 = 64
$ 45
multiply 60x.75 = 45
Answer:
y=-4+-1
Step-by-step explanation:
hope this is what your looking for
