Answer:
Step-by-step explanation:
Given
equation of circle 
Equation of tangent passing through (1,1)
Slope of tangent is given by differentiating equation of circle


at 

Equation of line with slope


270=2b + a
420=2a + 3c (you have to use trial and error for this)
B = 120
A = 30
C = 120
Just to check
270 = (2x120) + 30
420 = (2x30) + (3x120)
Answer:
A. 3.7
Step-by-step explanation:
3900/1050 = 3.7
1. 36 = 6·6 and 42 = 6·7 have a common factor of 6.
... x⁴ and x² have a common factor of x²
The GCF is 6x².
The factorization is 36x⁴ -42x² = 6x²(6x² -7)
2. All coefficients are multiples of 4. All variable factors are multiples of x³.
The GCF is 4x³.
The factorization is 4x⁵ -8x⁴ -4x³ = 4x³(x² -2x -1)
3. The GCF of coefficients 6 and 15 is (15 mod 6) = 3, which is also a factor of the other coefficients. The lowest power of m, which is m² is also a factor of the other terms.
The GCF is 3m².
The factorization is 6m⁵ -15m⁴ -21m³ +27m² = 3m²(2m³ -5m² -7m +9)
Answer:
idk
Step-by-step explanation: