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4 years ago

A chees player played 20 games total . If he won 2 of games, what is the ratio of games he lost to games he won ?

2 answers:

7 0

He played 20 and won 2, this means that he lost 18. The way to write a ratio is this (firsts answer:second answer). So your answer is 18:2

eduard4 years ago

6 0

-- He played 20 games.
-- He won 2 of them.
-- He must have lost (20 - 2) = 18 games.

The ratio of (games lost) to (games won) is 18 to 2, or 9 to 1 .

He ought to consider taking up a different game, other than chees.

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An automobile manufacturer claims that its jeep has a 53.9 miles/gallon (MPG) rating. An independent testing firm has been contr

Advocard [28]

Answer:

Value of the test statistic, $z_{test} = - 1.17$

Step-by-step explanation:

Null hypothesis, $H_{0}: \mu = 53.9$

Alternative hypothesis, $H_{a} : \mu \neq 53.9$

Sample mean, $\bar{X} = 53.7$

Sample size, n = 110

Standard deviation, $\sigma = 1.8$

Significance level, $\alpha = 0.02$

The value of the test statistics is given by the formula:

$z_{test} = \frac{\bar{X} - \mu}{\frac{\sigma}{\sqrt{n} } } \\z_{test} = \frac{53.7 - 53.9}{\frac{1.8}{\sqrt{110} } } \\z_{test} = - 1.17$

7 0

3 years ago

See image for question.

kotegsom [21]

Answer:

(a)

<u>Sample space:</u>

1*1, 1*2, 1*3, 1*4,
2*1, 2*2, 2*3, 2*4,
3*1, 3*2, 3*3, 3*4,
4*1, 4*2, 4*3, 4*4

Total 16 outcomes

(b)

(i) P(even) = 12/16 = 3/4
(ii) P(3x) = 7/16
(iii) P(perfect square) = 4/16 = 1/4

(a) <u>Sample space:</u>

1T, 1H, 2T, 2H, 3T, 3H, 4T, 4H

Total 8 outcomes

(b)

(i) 1T, 3T

P(T and odd) = 2/8 = 1/4

(ii) 1H, 4H

P(H and square) = 2/8 = 1/4

(iii) 1H, 2H, 3H, 4H

P(H) = 4/8 = 1/2

6 0

3 years ago

Which expression is equivalent to 4/9 times 7

11111nata11111 [884]

Answer:

4/9 * 7 =3.11111111

Step-by-step explanation:

4/9 * 7 =3.11111111

8 0

3 years ago

Read 2 more answers

I'M OFFERING 20 POINTS-

Dafna11 [192]

Answer:

Third option is correct. Scale factor 3 ; enlargement.

Step-by-step explanation:

It is given that the figure A'B'C'D' is a dilation of figure ABCD.

We know that after dilation the corresponding sides of image and preimage are in the same proportion.

The image of AD is A'D'.

From the figure it is noticed that the A(-1,2), D(-1,-1), A'(-3,6) and D'(-3,-3).

Distance formula is

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$AD=\sqrt{(-1+1)^2+(-1-2)^2}=\sqrt{9}=3$

$A'D'=\sqrt{(-3+3)^2+(-3-6)^2}=\sqrt{81}=9$

Scale factor is constant which represents the relation between image and preimage.

$k=\frac{A'D'}{AD}$

$k=\frac{9}{3}$

$k=3$

Therefore the scale factor is 3.

If k>0 it means enlargement and if k<0 it means reduction. Therefore third option is correct.

3 0

4 years ago

Read 2 more answers

Can you guys help me out pls

maks197457 [2]

D. 1.0002

Probabilities can only go up to 100%, or 1. 1.0002 is greater than 1.

5 0

4 years ago