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beks73 [17]
3 years ago
12

Can you guys help me out pls

Mathematics
1 answer:
maks197457 [2]3 years ago
5 0
D. 1.0002

Probabilities can only go up to 100%, or 1. 1.0002 is greater than 1.
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Find the first 3 terms of arithmetic sequence if t5=-154 and t9=-274. find t1, t2, t3
777dan777 [17]

Answer: t1 = -34; t2 = -64; t3 = -94

d is the distance between numbers (d > 0)

we have:

t5 = t1 + 4d = -154

t9 = t1 + 8d = -274

we have the equations:

t1 + 4d = -154

t1 + 8d = -274

<=> t1 = -34

      d = -30

with t1 = -34 and = -30 => t2 = -34 - 30 = -64

                                          t3 = -64 - 30 = -94

Step-by-step explanation:

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How many solutions does the equation below have? 1/(-6-8x) = -3- 1x​
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This equation has 2 solutions.

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14) Simplify. 6(3x - 5) + 2(3x - 5) - 8(3x - 5)
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An arithmetic sequence "a" starts with 84, 77 define "a" recursively
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Answer:

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In an arithmetic sequence, the difference between any two consecutive terms is always the same.

Then we can write it in a general way as:

aₙ = a₁ + (n - 1)*d

where:

aₙ is the n-th term of the sequence.

d is the constant difference between two consecutive terms.

a₁ is the initial term of our sequence.

Now in this case we know that the first terms of our sequence are:

84, 77, ...

Then we know the initial term of our sequence:

a₁ = 84.

And the value of d can be calculated as:

d = a₂ - a₁ = 77 - 84 = -7

Then the general way of writing this sequence is:

aₙ = 84 + (n - 1)*(-7)

And the recursion relation is:

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