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olganol [36]
3 years ago
14

I'M OFFERING 20 POINTS-

Mathematics
2 answers:
DochEvi [55]3 years ago
8 0

she is correct even check myself so it is scale factor 3; enlargement

Dafna11 [192]3 years ago
3 0

Answer:

Third option is correct. Scale factor 3 ; enlargement.

Step-by-step explanation:

It is given that the figure A'B'C'D' is a dilation of figure ABCD.

We know that after dilation the corresponding sides of image and preimage are in the same proportion.

The image of AD is A'D'.

From the figure it is noticed that the A(-1,2), D(-1,-1), A'(-3,6) and D'(-3,-3).

Distance formula is

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

AD=\sqrt{(-1+1)^2+(-1-2)^2}=\sqrt{9}=3

A'D'=\sqrt{(-3+3)^2+(-3-6)^2}=\sqrt{81}=9

Scale factor is constant which represents the relation between image and preimage.

k=\frac{A'D'}{AD}

k=\frac{9}{3}

k=3

Therefore the scale factor is 3.

If k>0 it means enlargement and if k<0 it means reduction. Therefore third option is correct.

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8 0
3 years ago
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Find the value of r so the line passes through each pair of points has the give slopes
Art [367]

Answer:

r=64

Step-by-step explanation:

First, let's start with what we have. If we use y=mx+b here's what we can put in:

y=-4x+b

Then we can use one of the given points to find the y-intercept. Since the only complete one is (12,10), we'll use that.

10=-4(12)+b\\10=-48+b\\58=b

So now we have y=-4x+58.

Now we can use our other point with the missing y-value and solve for y.

r=-4(-2)+58\\r=64

So the missing value is 64.

Hope this helps!

7 0
2 years ago
This graph represents the path of a baseball hit during practice.
zaharov [31]

Answer:

Step-by-step explanation:

x-coordinate of the vertex is the time the baseball reaches maximum height.

4 0
3 years ago
Points A, B, and C are collinear. Point B is between A and C. Solve for x if AC = 3x + 3, BC = 3, and AB = 2x + 2.
Ksenya-84 [330]

Answer:

x=2.

Step-by-step explanation:

It is given that points A, B, and C are collinear. Point B is between A and C.

Using segment addition property, we get

AC=AB+BC

It is given that AC = 3x + 3, BC = 3, and AB = 2x + 2.

3x+3=(2x+2)+3

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Isolate variable terms.

3x-2x=5-3

x=2

Therefore, the value of x is 2.

5 0
3 years ago
(cot^2x - 1)/(csc^2x) = cos2x​
Alex787 [66]

Answer:

Step-by-step explanation:

The idea here is to get the left side simplified down so it is the same as the right side. Consequently, there are 3 identities for cos(2x):

cos(2x)=cos^2x-sin^2x,

cos(2x)=1-2sin^2x, and

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We begin by rewriting the left side in terms of sin and cos, since all the identities deal with sines and cosines and no cotangents or cosecants.  Rewriting gives you:

\frac{\frac{cos^2x}{sin^2x} -\frac{sin^2x}{sin^2x} }{\frac{1}{sin^2x} }

Notice I also wrote the 1 in terms of sin^2(x).

Now we will put the numerator of the bigger fraction over the common denominator:

\frac{\frac{cos^2x-sin^2x}{sin^2x} }{\frac{1}{sin^2x} }

The rule is bring up the lower fraction and flip it to multiply, so that will give us:

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And canceling out the sin^2 x leaves us with just

cos^2x-sin^2x which is one of our identities.

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