So a times 10^n where 1≤|a|<10 and n is an integer is what i learned
so
a.
234=
2.34 times 100=
2.34 times 10²
b.
0.000052=
5.2 times 1/100000=
5.2 times 10⁻⁵
c.
-220000=
-2.2 times 100000=
-2.2 times 10⁵
d. ok, so just count the spaces moved to the left
-18.2 times 10⁻¹⁵
Answer:
the original volume is lesser than the new volume by 242.47 in³
Step-by-step explanation:
Volume of a cone is;
V = ⅓πr²h
Where;
r is radius
h is height
For the original chamber;
r = 5.7/2 = 2.85 inches
h = 12 inches
Volume of this original chamber is;
V_orig = ⅓ × π × 2.85² × 12
V_orig = 102.02 in³
In the new design, the chamber is scaled by a factor of 1.5.
Thus;
r_new = 2.85 × 1.5 = 4.275 inches
h_new = 12 × 1.5 = 18 inches
V_new = ⅓ × π × 4.275² × 18
V_new = 344.49 inch³
V_new - V_orig = 344.49 - 102.02 =
Thus, the original volume is lesser than the new volume by 242.47 in³
Answer:

Step-by-step explanation:
x+2/3x - 1/x-2 = x-3/3x

LCD is (3x)(x-2). so we multiply the whole equation by LCD

We multiply each term by LCD


There are 6 other positions in the string, each with 26 choices. So if you fix BO as the first two letters, there are

possible strings that you can make.
If BO is at the end of the string, you still have

possible strings.
Together, then, you have

possible strings.