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N76 [4]
3 years ago
13

PLEASE HELPPPPP I WILL GIVE BRAINLIESTT

Mathematics
2 answers:
mamaluj [8]3 years ago
7 0

Answer:

214

Step-by-step explanation:

A box is a shape of a cuboid. Use formula 2lw+2lh+2wh

Karo-lina-s [1.5K]3 years ago
4 0
It’s the second option 214in
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1. In a 30-60-90 triangle, the length of the hypotenuse is 6. What is the length of the shortest
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b. 3

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3 years ago
A piece of wire of length 56 is​ cut, and the resulting two pieces are formed to make a circle and a square. Where should the wi
Llana [10]

Answer:

1) Cut the wire at a distance of 31.36 and draw this length into a square and the remaining into a circle to minimize the area.

2) To maximize the area do not cut the wire but make the whole wire into a circle.

Step-by-step explanation:

let the wire be cut at a distance of x

We make a square of this wire

For the remaining length of (56 - x) we make a circle

Thus

Area of square = Area_{square}(side)^{2}\\\\=(x/4)^{2}

Similarly the area of the circle equals

A_{circle}=\frac{(56-x)^{2}}{4\pi }

Thus summing the areas we get

A=\frac{x^{2}}{16}+\frac{(56-x)^{2}}{4\pi }

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Thus we have

\frac{dA}{dx}=\frac{d(\frac{x^{2}}{16}+\frac{(56-x)^{2}}{4\pi })}{dx}\\\\0=\frac{x}{8}-\frac{(56-x)}{2\pi }\\\\\frac{x}{8}+\frac{x}{2\pi }=\frac{28}{\pi }\\\\\therefore x=31.36

Thus the length of the square wire should be x = 31.36

The length of the circular portion should be 56 - 31.36 = 24.64.

These lengths shall give the minimum combined area of the 2 figures.

2) Since the given function is a quadratic thus with the graph attached below we can see the maximum area occurs if all the wire is to be made into a circle thus to maximize the area the wire shall not be cut and wholly shaped into a circle.

4 0
3 years ago
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