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IRINA_888 [86]
3 years ago
13

(05.01)Dawn is making an abstract painting with two triangles. The dimensions of the painting are shown below: Two triangles sha

re the same height of 8 inches. One triangle has a base of 6 inches and the other is 10 inches. The total area of the two triangles is _____ square inches. Numerical Answers Expected! Answer for Blank 1:
Mathematics
2 answers:
kotegsom [21]3 years ago
8 0

Answer:

64

Step-by-step explanation:

The area of a triangle is found using the formula

A = 1/2bh

For the first triangle, the base is 6 and the height is 8:

A = 1/2(6)(8) = 3(8) = 24 sq. in.

For the second triangle, the base is 10 and the height is 8:

A = 1/2(10)(8) = 5(8) = 40 sq. in.

The total area will be the sum of these two areas:

24+40 = 64 sq. in.

QveST [7]3 years ago
3 0
Multiply the height by the base to get the area. 8 x 6 = 48. The area of the first triangle is 48 square inches. 8 x 10 = 80. The area of the second triangle is 80 square inches.
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What is the slope of the line from the table below hour: 1, 2, 4, 8 distance: 50, 100, 200, 400
VLD [36.1K]

Answer:

50

Step-by-step explanation:

The slope is change in y divided by the change in x

Change in distance / change in hour

m = (400-200)/(8-4)

   = 200/4

  = 50

4 0
3 years ago
A clock has a diameter of 16 cm. How long is the metal band around it?
kramer

Answer:

The length of  metal band around the given clock  is 50. 24 cm.

Step-by-step explanation:

Here, the diameter of given clock = 16 cm

Now, Diameter = 2 x Radius

So,  Radius  = D/2  = 16 cm/2  = 8 cm

⇒The radius of the clock = 8 cm

Now, The metal Band around it = The CIRCUMFERENCE of the watch

Circumference of the clock  = 2 π r

=  2 x ( 3.14) x ( 8)  = 50.24 cm

or, C = 50.24 cm

Hence, the length of  metal band around the given clock  is 50. 24 cm.

6 0
3 years ago
Whats the difference between range and interquartile range?
miv72 [106K]

Answer:

Step-by-step explanation:

The range is the difference between the highest and the lowest values in a set of data.  The interquartile range, the IQR, is what's "inside" the box in a box plot, which consists of the difference between the central measures, which are the first and the third quartiles.

3 0
3 years ago
Points E, F, and D are on circle C, and angle G measures 60°. The measure of arc EF equals the measure of arc FD.
galben [10]

Answer:

∠EFD ≅ ∠EGD ⇒ A

Arc ED ≅ arc FD ⇒ C

m arc FD = 120° ⇒ E

Step-by-step explanation:

Let us revise some facts

  1. Equal chords subtended equal arcs
  2. The measure of an inscribed angle is one-half the measure of the central angle which subtended by the same arc
  3. The measure of a central angle is equal to the measure of its subtended arc
  4. If one angle of an isosceles triangle measure 60° then the triangle is equilateral
  5. The sum of the measures of the interior angles of any quadrilateral is 360°

In the quadrilateral  CDGE

∵ m∠G = 60°

∵ m∠GDC = m∠GEC = 90°

- By using the 5th rule above

∴ m∠G + m∠GDC + m∠DCE + m∠GEC = 360°

∴ 60 + 90 + m∠DCE + 90 = 360

∴ 240 + m∠DCE = 360

- Subtract 240 from both sides

∵ m∠DCE = 120°

In circle C

∵ ∠DCE is a central angle subtended by arc DE

∵ ∠DFE is an inscribed angle subtended by arc DE

- By using the 2nd rule above

∴ m∠DFE = \frac{1}{2} m∠∠DCE

∵ m∠DCE = 120°

∴ m∠DFE = \frac{1}{2} (120)

∴ m∠DFE = 60°

- That means ∠EFD ≅ ∠EGD because their measure is 60°

∴ ∠EFD ≅ ∠EGD

In Δ EFD

∵ EF = FD

∵ m∠DFE = 60°

- By using the 4th rule above

∴ Δ EFD is an equilateral triangle

∴ ED = FD = FE

In circle C

∵ Side ED subtended by arc ED

∵ Side FD subtended by FD

∵ Side ED ≅ side FD ⇒ proved

- By using the 1st rule above

∴ Arc ED ≅ arc FD

∵ m∠ECD = 120°

∵ ∠ECD is a central angle subtended by arc ED

- By using the 3rd rule above

∴ m∠ECD = m arc ED

∴ m of arc ED = 120°

∵ Arc ED ≅ arc FD

∴ m arc ED = m arc FD

∴ m arc FD = 120°

5 0
2 years ago
Read 2 more answers
I have no idea how to do this, so if someone could at least do one of these I’ll be grateful <3
jenyasd209 [6]

Answer:

Answers are below!

Step-by-step explanation:

(2 + g) (8)

= (2 + g) (8)

Add a 8 after the 2, and flip.

= (2)(8) + (g)(8)

= 16 + 8g

= 8g + 16

= (4) (8 + -5g)

Add another 4, then flip.

= (4) (8) + (4) (-5g)

= 32 − 20g

= - 20g + 32

−7 (5-n)

= (−7) (5 + -n)

Add another 7, then flip.

= (−7) (5) + (-7) (-n)

= −35 + 7n

= 7n - 35

Use the distributive property.

a (b + c) = ab + ac

a = 8

b = 2m

c = 1

= 8 × 2m + 8 × 1

Simplify, you get 16m + 8.

Use the distributive property.

a (b + c) = ab + ac

a = 6x

b = y

c = z

= 6xy - 6xz is the answer.

\mathrm{Apply\:the\:distributive\:law}:\quad \\\:a\left(b+c\right)=ab+ac

a=-3,\:b=2b,\:c=2a

=-3\cdot \:2b+\left(-3\right)\cdot \:2a

Apply minus plus rules.

=-3\cdot \:2b+\left(-3\right)\cdot \:2a

Multiply the numbers.

3 x 2 = 6

7 0
3 years ago
Read 2 more answers
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