Sub in 4 as x
3(4) - 29
= -17
The interquartile range is 12-6=6
Answer:
Given:-
The length of copper wire (L) = 270 cm
Area of cross-sectional (A) = 0.030 
and specific resistance (ρ) =
ohm-cm.
Use the formula R=(Specific resistance*L)/A, to calculate the Resistance(R)
then,
ohm
Simplify:
R = 0.0162 ohm =
ohm
Therefore, the resistance of copper wire is,
Ω
The answer to this question is 100% B: y=2x+7 I hope this helped you! :)
Answer:
30
Step-by-step explanation:
24 - (-6)
Apply rule : -(-a) = a
Negative (-) times a negative (-) is positive (+).
24 + 6
= 30