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Anna35 [415]
3 years ago
12

A spinner travels around a circle. The radius is 3 inches. Mike spins the spinner and it travels completely around the circle 5

times. About how far did the tip of the spinner travel?
Mathematics
2 answers:
nignag [31]3 years ago
7 0

Answer:

The spinner travelled 94.2 inches.

Step-by-step explanation:

In order to solve this question we first need to calculate the length of the circle, that is given by the following formula:

length = 2*pi*r

length = 2*3.14*3 = 18.84 inches

Since the spinner revolved around the circle 5 times, the distance travelled by the tip is the length of the circle multiplied by 5, as shown below:

distance = length*5

distance = 18.84*5 = 94.2 inches

The spinner travelled 94.2 inches.

Elis [28]3 years ago
4 0

Answer:

94.2 inches.

Step-by-step explanation:

The length of the circle can be determined by

length 'l'= 2πr

l = 2 x 3.14 x 3 = 18.84 inches

As the spinner and it travels completely around the circle 5 times, therefore, we'll have the distance of

distance = l x 5

distance = 18.84 x 5 => 94.2 inches

Thus, the tip of the spinner traveled 94.2 inches.

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Answer:

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Step-by-step explanation:

You want the area under the curve f(x) = √(3x+5) on the interval [0, 4] estimated using the left sum and four subintervals.

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When the interval [0, 4] is divided into four equal parts, each has unit width. That means the area of the rectangle defined by the curve and the interval width will be equal to the value of the curve at the left end of the interval.

The area we want is the sum ...

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__

<em>Additional comment</em>

The table values in the attachment are rounded to 7 decimal places. Trailing zeros are not shown. Actual values used have 12 significant digits, as the total shows.

Such a sum is called a Riemann sum, named for a German mathematician. Four such sums are commonly used, and further refinements are possible. Those are the left sum (as here), the right sum, the midpoint sum, and a sum using a trapezoidal approximation of the rectangle area.

For left, right, and midpoint sums, n function values are required for n subintervals. When the trapezoidal approximation is used, n+1 function values are required.

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