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Kobotan [32]
3 years ago
10

Two cars are approaching an intersection on roads that are perpendicular to each other. Car A is north of the intersection and t

raveling south at 60 mph. Car B is east of the intersection and traveling west at 45 mph. How fast is the distance between the cars changing when car A is 14 miles from the intersection and car B is 48 miles from the intersection? (Round your answer to two decimal places.)
mph?
Mathematics
1 answer:
AURORKA [14]3 years ago
7 0

Answer:

q = 4506.

Step-by-step explanation:

2p2q = 30,000 + 9000p2.

(a) Find the elasticity when

p = $50

and

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Answer:

C $113.40

Step-by-step explanation:

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Number 11 please , someone? Thank you .
KIM [24]
In a triangle, the measure of an angle is in the same order of size as the length of the opposite side. The smallest angle is opposite the shortest side. The largest angle is opposite the longest side. The middle-sized angle is opposite the middle-sized side.

Also, in a triangle, the sum of the measures of the interior angles is 180.

We can now calculate the measures of the three angles by writing and solving an equation.

m<A + m<B + m<C = 180

9x - 7 + 7x - 9 + 28 - 2x = 180

Collect like terms on the left side.

9x + 7x - 2x - 7 - 9 + 28 = 180

14x + 12 = 180

Subtract 12 from both sides.

14x = 168

x = 12

Now that we know x, we can find the measure of each angle.

m<A = 9x - 7 = 9(12) - 7 = 108 - 7 = 101
m<B = 7x - 9 = 7(12) - 9 = 84 - 9 = 75
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(Quick check: Add the angles measures: 101 + 75 + 4 = 180. The sum is 180 as it should be.)

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