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vova2212 [387]
3 years ago
14

maria compro 6 bolsas de cafe cada una de 250,75gramos cual fue la cantidad de gramos que compro maria

Mathematics
2 answers:
marissa [1.9K]3 years ago
7 0
Yo creo que es 1,504.5 gramos en total que compro María!!
Mariulka [41]3 years ago
6 0
En total María compró 1,504.50 gramos.

Yo se esto porqué
1 bolsa = 250.75 gramos
Entonces para encontrar cuantos gramos hay en 6 bolsas tienes que multiplicar 250.75*6
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5 0
2 years ago
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Suppose you want to build a fish tank in the shape of a right rectangular box with square base and no top which will hold 6 cubi
AlekseyPX
You must develop a cost function C(x) and then minimize its value.
How much dwill the glass cost?  It's $1 per sq ft, and the total area of the glass is 4(xh), where x is the length of one side of the base and h is the height of the tank.  The area of the metal bottom is x^2, which we must multiply by $1.50 per sq ft. 

This cost function will look like this:  C(x) = 4($1/ft^2)xh + ($1.50/ft^2)x^2

but we know that (x^2)h= 6 cu ft, or h = (6 cu ft) / (x^2).  Subst. this last result into the C(x) equation, immediately above:

C(x) = 4($1/ft^2)x[6 ft^3 / x^2] + ($1.50/ft^2)x^2

Let's focus on the numerical values and ditch the units of measurement for now:

C(x) = 4x(4/x^2) + 1.50x^2, or

C(x) = 16/x + 1.5x^2

Differentiate this with respect to x:

C '(x) = -16 / x^2 + 3 x

Set this equal to 0 and solve for x:    -16/x^2 = -3x, or 16 = 3x^3

Then x^3 = 16/3, and x = 5 1/3 ft.  We already have the formula  

(x^2)h= 6 cu ft, so if x = 5 1/3, or 16/3, then (16/3)^2 h = 6, or

h = 6 / [16/3]^2.

h = 6 (9/256) = 0.21 ft.  While possible, this h = 0.21 ft seems quite unlikely.


Please work through this problem yourself, making sure you understand each step.  If questions arise, or if you find an error in my approach, please let me know.

Once again:
1.  Write a formula for the total cost of the material used:  4 sides of dimensions xh each, plus 1 bottom, of dimensions x^2.  Include the unit prices:  $1 per square foot for the sides and $1.50 per square foot for the bottom.
2.  Differentiate C(x) with respect to x.
3.  Set C '(x) = 0 and solve for the critical value(s).
4.  Calculate h from your value for x.
5.  Write the dimensions of the tank:  bottom:  x^2; height:  h
4 0
3 years ago
Look at attachment below
Romashka [77]
I think it’s 8/55=4/x
So it’s 8x=4(55)
8x=220
x=220/8
x=27.5
4 0
3 years ago
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