It’s probably true as matter is either gas liquid or solid
Answer:
a

b

c

Step-by-step explanation:
Generally the size of the sample sample space is mathematically represented as

Where N is the total number of objects available and r is the number of objects to be selected
So for a, where N = 19 and r = 8



For b Where N = 25 and r = 3



For c Where N = 23 and r = 2



The first reaction represented is a decomposition reaction due to the fact the bonded pair are being split apart.
The second equation is a single displacement because the B and C have switched places, which is the only change making it a single displacement. If there had been another bond and A had also moved, it would be double.
1. 5 and E, 6 and F, 7 and D, 8 and A, 9 and G
Answer:
see below
Step-by-step explanation:
some of your answers that you currently have are wrong, I'll note those mistakes below
- when factoring (ie 5x+15) only factor out things that can divide both numbers into a whole number ratio
5x+15 = 5(x+3), not (x+3)(x+5)
ie 
we see that 10x can divide the numerator in a whole number ratio
= 10x(x+2), not (x+2)(x+10)
second mistake: the first binomial expansion is incorrect.
you have the expansion formula right, but you added terms wrong, go look at it again
3. x^2+3x+2/ x^2+5x+6
(x+1)(x+2)/(x+3)(x+2)
(x+1)/(x+3)
4. (x^2+6x+8)/(x^2-16)
(x+4)(x+2)/(x+4)(x-4)
(x+2)/(x-4)
5. we can't simplify that any more, x and y are different variables so therefore we cannot cross out stuff on numerator and denominator
6. (x^4y^6)^2
(x^4y^6)(x^4y^6) = 
remember that (x^a)(x^b) = x^(a+b)
or remember that (x^a)^b = x^ab