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Daniel [21]
3 years ago
11

Please help me please! Also, please show your work image shown below in attachment

Mathematics
1 answer:
WINSTONCH [101]3 years ago
6 0

Answer:

see below

Step-by-step explanation:

some of your answers that you currently have are wrong, I'll note those mistakes below

- when factoring (ie 5x+15) only factor out things that can divide both numbers into a whole number ratio

5x+15 = 5(x+3), not (x+3)(x+5)

ie  \frac{10x^2+20x}{x+2}

we see that 10x can divide the numerator in a whole number ratio

10x^2+20x = 10x(x+2), not (x+2)(x+10)

second mistake: the first binomial expansion is incorrect.

you have the expansion formula right, but you added terms wrong, go look at it again

3. x^2+3x+2/ x^2+5x+6

(x+1)(x+2)/(x+3)(x+2)

(x+1)/(x+3)

4. (x^2+6x+8)/(x^2-16)

(x+4)(x+2)/(x+4)(x-4)

(x+2)/(x-4)

5. we can't simplify that any more, x and y are different variables so therefore we cannot cross out stuff on numerator and denominator

6. (x^4y^6)^2

(x^4y^6)(x^4y^6) = x^8y^{12}

remember that (x^a)(x^b) = x^(a+b)

or remember that (x^a)^b = x^ab

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Cuboid ABCDEFGH is shown
gtnhenbr [62]

Answer:

The angle formed between CF and the plane ABCD is approximately 47.14°

Step-by-step explanation:

The given parameters are;

BC = 6.8

DE = 9.3

∠BAC = 52°

We note that the angles formed by the vertex of a cuboid are right triangles, therefore, by trigonometric ratios, we get;

sin∠BAC = BC/(The length of a line drawn from A to C)

∴ The length of the line drawn from A to C = BC/sin∠BAC

The length of the line drawn from A to C = 6.8/sin(52°) ≈ 8.63

∴ AC = 8.63

By trigonometry, we have;

The angle formed between CF and the plane ABCD = Angle ∠ACF

tan\angle X = \dfrac{Opposite \ leg \ length}{Adjacent\ leg \ length}

tan\angle ACF = \dfrac{FA}{AC}

In a cuboid, FA = BG = CH = DE = 9.3

\therefore tan\angle ACF = \dfrac{9.3}{8.63}

\therefore \angle ACF = arctan \left(\dfrac{9.3}{8.63} \right) \approx 47.14^{\circ}

The angle formed between CF and the plane ABCD = Angle ∠ACF ≈ 47.14°

4 0
3 years ago
Ihorangi travels 51 km to work and 51 km from work each day.
viktelen [127]

Answer:

Ihorangi uses 7.65 litres of petrol to and from work

Step-by-step explanation:

If the car Ihorangi drives consumes 7.5 L/100 km

Then for 1 km journey, the car will consume 7.5/100 L

= 0.075 L

If Ihorangi travels 51 km to work and 51 km from work

Therefore Ihorangi travel (51 + 51) km daily to and from work

= 102 km daily

The fuel he consumes daily is 102*0.075 L

= 7.65 L

7 0
3 years ago
I need to write a decimal where the value of a digit is 1/10 as much as a digit in another place
KengaRu [80]
1/10 is the same as saying 10 times less

Refer to the diagram below
The digit as the first decimal place is worth 1/10
The digit as the second decimal place is worth 1/100 which is 1/10 worth the digit as the first decimal place

Example of two decimal numbers:

2.56 and 2.68

The digit 6 in 2.56 is 6/100
The digit 6 in 2.68 is 6/10

The digit 6 in 2.56 is 1/10 as much as the digit 6 in 2.68

6 0
3 years ago
Help me please!!!!!!!
yawa3891 [41]
The answer would be B
7 0
3 years ago
A line crosses the coordinates (-3,5) and (4,-2). What is the slope of the line?
ICE Princess25 [194]

Answer:

Slope = -1

Step-by-step explanation:

\frac{-2-5}{4-(-3)}=\frac{-7}{7} =-1

8 0
3 years ago
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