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ratelena [41]
3 years ago
12

Subtract −b+3 ​​from −11b−4 ​. What is the answer?

Mathematics
2 answers:
adelina 88 [10]3 years ago
8 0
That is the same as (-11b-4)-(-b+3)[/tex}.  Negatives are gross, so let's distribute it.  Remember, that negative can be turned into a positive by changing the sign on every term in the parentheses.  It's called distributing the negative.  So we can change it to [tex](-11b-4)+(b-3).  Now it's just basic addition.

-11b-4+b-3  =  -10b-7

So your final answer is:

-10b-7
monitta3 years ago
5 0
-11b-4 - -b+3 = -10b-7
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Please help im very stuck
liraira [26]

Answer:

The answer is D!!!

Step-by-step explanation:

In the attachment!

I plugged in that equation into a graphing calculator and got this....

since it's also a (<, >) sin, we know that it's dotted.....

Hope this helps!

6 0
3 years ago
I answered it but I just need someone to answer just to make sure mine are right
Artemon [7]
<h2>The missing measures of the angles are:</h2>

m\angle 1= 60^{\circ}\\\\m\angle 2= 39^{\circ}\\\\m\angle 3= 21^{\circ}\\\\m\angle 4 = 39^{\circ}\\\\m\angle 5 = 21^{\circ}

<u>Given</u>:

m\angle Z = 138^{\circ}

<em><u>Note the following:</u></em>

  • An equilateral triangle has all its three angles equal to each other. Each angle = 60^{\circ}.
  • This implies that, since \triangle WXY is equilateral, therefore, m\angle Y = m\angle XWY = m\angle XYW = 60^{\circ}

  • Base angles of an isosceles triangle are congruent to each other.
  • This implies that, since \triangle WZY is isosceles, therefore, m\angle 3 = \angle 5

Applying the above stated, let's find the measure of each angle:

  • Find m\angle 1

m\angle 1 = 60^{\circ} (an angle in an equilateral triangle equals 60 degrees)

  • Find m\angle 2

m\angle 2 = 60 - m \angle 3

m\angle 2 = 60 -\frac{1}{2}(180 - 138) (Note: \frac{1}{2}(180 - 138) = 1 $ base $ angle $ of $ \triangle WZY)

m\angle 2 = 60 -21\\\\m\angle 2 = 39^{\circ}

  • Find m\angle 3 and m\angle 5 (base angles of isosceles triangle WZY)

m\angle 3 =  \frac{1}{2}(180 - 138) (1 $ base $ angle $ of $ \triangle WZY)

m\angle 3 =  \frac{1}{2}(42) \\\\m\angle3 = 21^{\circ}

m\angle3 = m\angle 5 (base angles of isosceles triangle are congruent)

Therefore,

m\angle5 = 21^{\circ}

  • Find m\angle 4

m\angle 4 = 60 - m\angle 5

Substitute

m\angle 4 = 60 - 21\\\\m\angle 4 = 39^{\circ}

The missing measures of the angles are:

m\angle 1= 60^{\circ}\\\\ m\angle 2= 39^{\circ}\\\\m\angle 3= 21^{\circ}\\\\m\angle 4 = 39^{\circ}\\\\m\angle 5 = 21^{\circ}

Learn more here:

brainly.com/question/2944195

5 0
2 years ago
What is the result of the operation
Anna35 [415]

Answer:

D.

Step-by-step explanation:

-2*-3=6        -2*5=-10.      -2*1=-2

-2*8=-16.      -2*-2=4.       -2*3=-6

-2*2=-4.       -2*1=-2.        -2*-4=8

6 0
3 years ago
9 — 3x = у<br> 3х – у = -2
Phoenix [80]

Answer:

This could be wrong, but i still wanted to help you.

Step-by-step explanation:

9-3x=y

+9      +9

3x=y

÷3   ÷3

x=y/3

Im sorry if this is wrong

6 0
3 years ago
Anyoneeee??????????
leva [86]

Your answer will be D

As y = -(x+2)(x-1)

Thus the external negative sign will flip the positive 2 into a negative & negative 1 into a positive; Resulting, y=(x-2)(x+1)

7 0
3 years ago
Read 2 more answers
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