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Alenkinab [10]
3 years ago
8

Algebra Help please?

Mathematics
1 answer:
tresset_1 [31]3 years ago
4 0

According to the table, f(x)=g(x) when x=0 because f(0)=g(0)=1, and when x=1 because f(1)=g(1)=0.25.

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Which point would be on the residual plot of the data
Korolek [52]

Answer:

C.  (3,0)

hope this help

4 0
3 years ago
Read 2 more answers
A collector offers to buy state quarters for $2000\%$ of their face value, which is 25 cents. At that rate how many dollars will
umka21 [38]

Answer:

Bryden will get a total of $20 for this four quarters

Step-by-step explanation:

Here, we have a collector offering to buy state quarters for 2,000% of their face value.

Now, we have 4 state quarters with the value of 1 being 25 cents.

Since 1 has a value of 25 cents, then four will have a face value of 25 cents * 4 = 100 cents or better still $1

Now, the offer is 2000%

So the amount to be paid in dollars will be 2000% of $1.

Mathematically, that would be;

2000/100 * 1 = 2000/100 = $20

6 0
2 years ago
Can I please get some help?<br><br><br><br> Having a bit of trouble.
Alekssandra [29.7K]
Well for f(x) = 2x²+2

1)
the domain is all possible values "x" can safely take, safely meaning, it has no foreseeable constraints, hmm , in this case, there aren't any, so "x" values can be ℝ, and thus the domain is ℝ

2)
the range, is all values f(x) gets, from all those mutations "x" takes, notice, you have 2x², if you make "x" some negative value like say, -1,000,000, then you'll end up with 2(-1,000,000)², which simply can be rewritten as 2(-1,000,000)(-1,000,000), now, negative times negative, is positive

that means, no matter which negative value "x" takes, the value coming out of 2x², will always be positive, and "x" is positive, the same, 2x² will spit out a positive value

so, f(x) will never be negative, since 2x²+2 will never give a negative value
the lowest f(x) can get is when x = 0, then you get 2(0)²+2, which is just 2

so, f(x) goes as low as 2, then goes back up, so the range is y ≥ 2

3)
to get the inverse of any expression, you start off by switching the variables
so, let's do so

\bf f(x)=y=2x^2+2\qquad inverse\implies x=2y^2+2\impliedby f^{-1}(x)&#10;\\\\\\&#10;\textit{now, let's solve for "y"}&#10;\\\\\\&#10;x-2=2y^2\implies \cfrac{x-2}{2}=y^2\implies \sqrt{\cfrac{x-2}{2}}=y\impliedby f^{-1}(x)

4)

the domain of the inverse, well, if two expressions are inverse of each other, say f(x) and g(x), are inverse of each other, the "domain of f(x), is the range of g(x)" and "the range of f(x) is the domain of g(x)"

so, what's the domain of the inverse? well, what's the "range" of f(x), is anything BUT below 2, well, that's also the domain for the inverse

5)

surely you know by now, what's the range of the inverse?  well, what's the domain of f(x)? is ℝ, so, that's the range of the inverse then
5 0
2 years ago
What is the reciprocal of 7 over 8
sattari [20]
  Hi There!

  You multiply by 1/1
so your Answer would be
            8/7

Hope this Helps!
3 0
3 years ago
Read 2 more answers
What are the two numbers
serious [3.7K]
X=2y/3
x+y=30

plug in the value of x in the second equation to have one variable in the equation...
2y/3+y=30
5y/3=30
then multiply 3 on both sides...
5y=90
divide by 5 on both sides...
y=18
and to solve for x you have to plug in y on either equation...
1st way to solve for x:
x+18=30
subtract 18 on both sides...
x=12
2nd way to solve for x:
x=(18)2/3
you then solve...
x=36/3
x=12

answer: 12,18
8 0
3 years ago
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