Question

2. The length of a rectangle is 5 feet more than the width. The perimeter of the rectangle is

Answer 1

In order to solve this let us for at assume that the value of the width is X. Therefore the length will be x+5.

We can now write an equation:

(X+5) + (X+5) + X + X = 58

Combining like terms we should get
4X + 10 = 58

Now subtract 10 from both sides to get
4x = 48

Divide by 4 now and you should get

X = 12

Now we know the value of X and therefore the width.