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anzhelika [568]
2 years ago
15

2. The length of a rectangle is 5 feet more than the width. The perimeter of the rectangle is

Mathematics
1 answer:
nevsk [136]2 years ago
7 0
In order to solve this let us for at assume that the value of the width is X. Therefore the length will be x+5.

We can now write an equation:

(X+5) + (X+5) + X + X = 58

Combining like terms we should get
4X + 10 = 58

Now subtract 10 from both sides to get
4x = 48

Divide by 4 now and you should get

X = 12

Now we know the value of X and therefore the width.
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The probability of getting two numbers whose sum is greater than 9 and less than 13 is \frac{1}{6}

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Given : A single​ 6-sided die is rolled twice.

To find : The probability of getting two numbers whose sum is greater than 9 and less than 13 ?

Solution :

The set of 36 equally likely outcomes,

          1              2              3              4               5             6

1 (1, 1) (1, 2) (1, 3) (1, 4) (1, 5) (1, 6)

2 (2, 1) (2, 2) (2, 3) (2, 4) (2, 5) (2, 6)

3 (3, 1) (3, 2) (3, 3) (3, 4) (3, 5) (3, 6)

4 (4, 1) (4, 2) (4, 3) (4, 4) (4, 5) (4, 6)

5 (5, 1) (5, 2) (5, 3) (5, 4) (5, 5) (5, 6)

6 (6, 1) (6, 2) (6, 3) (6, 4) (6, 5) (6, 6)

Getting two numbers whose sum is greater than 9 and less than 13

The favorable outcome is (4,6),(5,5),(5,6),(6, 4),(6, 5),(6, 6) = 6

The probability is given by,

\text{Probability}=\frac{\text{Favorable Outcome}}{\text{Total Outcome}}

\text{Probability}=\frac{6}{36}

\text{Probability}=\frac{1}{6}

Therefore, The probability of getting two numbers whose sum is greater than 9 and less than 13 is \frac{1}{6}

5 0
3 years ago
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