Given: △EDN∼△LKI, DQ , KO are altitudes, DN=12, KI=4, DQ=KO+6. Find: QN and OI.
1 answer:
Answer:
- QN = 3√7
- OI = √7
Step-by-step explanation:
The ratio of corresponding sides DN and KI is 12 : 4 = 3 : 1. The same ratio applies to altitudes DQ and KO. Since the difference between these altitudes is 6 and the difference between their ratio units is 3-1 = 2, each ratio unit must stand for 6/2 = 3 units of linear measure. That is, ...
DQ = (3 units)·3 = 9 units
KO = (3 units)·1 = 3 units
Then the base lengths QN and OI can be found from the Pythagorean theorem:
KI² = KO² +OI²
4² = 3² +OI²
OI = √(16 -9)
OI = √7
QN = 3·OI = 3√7
You might be interested in
Answer:
A
Step-by-step explanation:
In the slope-intercept form (y=mx+c), the coefficient of x is the slope and c is the y-intercept.
<u>g(x)= -6x +3</u>
Slope= -6
y- intercept= 3
<u>f(x)</u>
y- intercept is the point at which the graph cuts through the y- axis, and it occurs at x= 0.
The two points on the graph are (0, 3) and (1, 1).
slope
= -2
y- intercept= 3
Thus, both have different slopes but the same y-intercepts.