Write the prime factorization of these numbers 18

6. Carrie buys 4.16 pounds of apples for $5.20. How much does 1 pound cost?

spayn [35]

$1.25
Hope I helped !!

8 0

2 years ago

I am a number between 60 and 100.My ones digital is less than my tens digit I am a prime number what number am i

Licemer1 [7]

Dear Cody1111, 97 is a possible number 7 is less than 9 and 97 is a prime number.

6 0

2 years ago

How to find a side in a right triangle with given hypotenuse?

tangare [24]

You need to know more information, not just the length of the hypotenuse.

If you know the length of one leg use Pythagoras theorem to find the other.

If you know the value of one other angle use trigononemtry

4 0

3 years ago

Can you please answer the question?

Roman55 [17]

The trigonometric expression $\frac{\tan^{2} \alpha}{\tan \alpha - 1} + \frac{\cot^{2} \alpha}{\cot \alpha - 1}$ is equivalent to the trigonometric expression $\sec \alpha \cdot \csc \alpha + 1$ .

<h3>How to prove a trigonometric equivalence</h3>

In this problem we must prove that one side of the equality is equal to the expression of the other side, requiring the use of algebraic and trigonometric properties. Now we proceed to present the corresponding procedure:

$\frac{\tan^{2} \alpha}{\tan \alpha - 1} + \frac{\cot^{2} \alpha}{\cot \alpha - 1}$

$\frac{\tan^{2}\alpha}{\tan \alpha - 1} + \frac{\frac{1}{\tan^{2}\alpha} }{\frac{1}{\tan \alpha} - 1 }$

$\frac{\tan^{2}\alpha}{\tan \alpha - 1} - \frac{\frac{1 }{\tan \alpha} }{\tan \alpha - 1}$

$\frac{\frac{\tan^{3}\alpha - 1}{\tan \alpha} }{\tan \alpha - 1}$

$\frac{\tan^{3}\alpha - 1}{\tan \alpha \cdot (\tan \alpha - 1)}$

$\frac{(\tan \alpha - 1)\cdot (\tan^{2} \alpha + \tan \alpha + 1)}{\tan \alpha\cdot (\tan \alpha - 1)}$

$\frac{\tan^{2}\alpha + \tan \alpha + 1}{\tan \alpha}$

$\tan \alpha + 1 + \cot \alpha$

$\frac{\sin \alpha}{\cos \alpha} + \frac{\cos \alpha}{\sin \alpha} + 1$

$\frac{\sin^{2}\alpha + \cos^{2}\alpha}{\cos \alpha \cdot \sin \alpha} + 1$

$\frac{1}{\cos \alpha \cdot \sin \alpha} + 1$

$\sec \alpha \cdot \csc \alpha + 1$

The trigonometric expression $\frac{\tan^{2} \alpha}{\tan \alpha - 1} + \frac{\cot^{2} \alpha}{\cot \alpha - 1}$ is equivalent to the trigonometric expression $\sec \alpha \cdot \csc \alpha + 1$ .

To learn more on trigonometric expressions: brainly.com/question/10083069

#SPJ1

6 0

2 years ago

NO LINKS, HELP IM GIVING BRAINLIEST TO CORRECT ANSWER

julsineya [31]

Answer:

100

Step-by-step explanation:

$8.(33) * \sqrt{144} = 8.(3) + \sqrt{144} = 8 \frac{1}{3} * 12 = \frac{25}{3} * 12 = 25 * 4 = 100$

3 0

2 years ago