A product is negative when the number of negative numbers in the multiples is odd.
Therefore, options A and C gives negative products.
Answer:
x-intercepts = 1,2, and 4, y-intercept = -8
Step-by-step explanation:
x^3 - 7x^2 - 14x - 8 in factored form is equal to (x-1)(x-2)(x-4).
Solving for x-intercepts:
- We are actually able to solve for all x-intercepts without the given factor. But since we are given one of the factors, our job becomes much easier.
- Using synthetic division, or long division, we factor out the x-intercept 4. Which leaves us with the polynomial x^2 - 3x + 2.
- From here we can separate the polynomial into two binomials.
- x^2 - 3x + 2 = (x-1)(x-2). Giving us all 3 x-intercepts.
- Using Descartes' rules we can identify before even starting the problem how many real x-intercepts there are (Not needed for this problem).
Solving for y-intercept:
- The y-intercept is always the coefficient that does not have any assigned x-variables.
- The coefficient is -8, thus the y-intercept.
- If unsure of the y-intercept, you can always plug in x = 0. Solving for the y-intercept will give you the value of f(0).
- If there is no coefficient, the y-intercept is equal to zero.
