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BabaBlast [244]
3 years ago
9

Using the triangle below, find the length of side c if side a is 15 and θ =55. Round your answer to the nearest tenth.

Mathematics
1 answer:
Kaylis [27]3 years ago
5 0

Answer:

15 sin 55 = 12

Step-by-step explanation:

It is a basic trigonometry formula

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Evaluate-2x3 - 2x2 - 4x-2 for x=-2.<br> A.-18<br> B. 16<br> C. -2<br> D. 14
dmitriy555 [2]

Answer:

14

Step-by-step explanation:

-2x^3 - 2x^2 - 4x-2

Let x = -2

-2 (-2)^3 - 2 (-2)^2 -4(-2) -2

Exponents first

-2 (-8) -2 (4) -4(-2) -2

Then multiply

16 -8 +8 -2

Then add and subtract

14

4 0
3 years ago
Please help thanks so much.
Alik [6]
You can see if they are similar by looking at the sides.

If each of the sides have the same proportion then they are similar.

24/3 = 8
32/4 = 8
112/14 = 8

Yes they are similar and their ratio is 1:8

Hope this helps :)
3 0
4 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=5x%5E%7B2%7D%2B%7Cx%2B1%7C%5C%20%5Ctextgreater%20%5C%200" id="TexFormula1" title="5x^{2}+|x+1|
Pavel [41]
5x² + |x+1| > 0
5x² + x + 1 > 0
x+1 > 0 because it came from absolute
5x² > 0 because it’s squared

When you try a number you should put it in the original equality
5x² + |x+1|
7 0
2 years ago
Help me please !!!!!!!
Natalka [10]

Answer: D

Step-by-step explanation:

h(x) is f(x) for x moving 4 units right.

h(x)=f(x-4) =√(x-4)

Answer D

7 0
3 years ago
Read 2 more answers
what �is the equation of a line that is perpendicular to the line  y = − 2 5 x − 5 y = - 2 5 x - 5 and passes thr
gladu [14]

Answer:

y=\frac{1}{25}x-\frac{31}{25}

Step-by-step explanation:

y=-25x-5

You can get the gradient of the line perpendicular to this as you know the products of their gradients will be -1.

-25*m_{perpendicular}=-1\\m_{perpendicular}=\frac{1}{25}

We have a gradient, and a point (6, 1), so we can now substitute our known values into the line equation.

(y-y_0)=m(x-x_0)

y-1=\frac{1}{25} (x-6)

Rearrange for y and collect terms.

y=\frac{1}{25}x-\frac{6}{25}-1\\\\y=\frac{1}{25}x-\frac{31}{25}

8 0
4 years ago
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