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Lostsunrise [7]
3 years ago
9

What is the sum of the first four composite numbers? 19 20 27 28

Mathematics
2 answers:
sukhopar [10]3 years ago
6 0

Answer:

I think 19 will be your answer

Tatiana [17]3 years ago
4 0
Your answer would be 27
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A sample of 100 people is classified by gender (male/female) and by whether they are registered voters. The sample consists of 8
uysha [10]

Answer:

12

Step-by-step explanation:

Given :

                                    Male         Female        Total

Registered                                                          60

Non registered                                                   40

Total                          20                  80    

Solution :

N= 100

Formula of expected frequency = E_{ij}=\frac{T_i \times T_j}{N}

E_{ij}= expected frequency for the ith row/jth columm.

T_i = total in the ith row

T_j= total in the jth column

N = table grand total.

So, using formula  E_{11}=\frac{T_1 \times T_1}{100}

E_{11}=\frac{60 \times 20}{100}

E_{11}=12

E_{12}=\frac{T_1 \times T_2}{100}

E_{12}=\frac{60 \times 80}{100}

E_{12}=48

E_{21}=\frac{T_2 \times T_1}{100}

E_{21}=\frac{40 \times 20}{100}

E_{21}=8

E_{22}=\frac{T_2 \times T_2}{100}

E_{22]=\frac{80 \times 40}{100}

E_{22}=32

Expected frequency table

                                    Male         Female        Total

Registered                  12                  48            60

Non registered           8                   32             40

Total                           20                  80    

So, the expected frequency for males who are registered voters are  E_{11}=12

5 0
3 years ago
Please calculate this limit <br>please help me​
Tasya [4]

Answer:

We want to find:

\lim_{n \to \infty} \frac{\sqrt[n]{n!} }{n}

Here we can use Stirling's approximation, which says that for large values of n, we get:

n! = \sqrt{2*\pi*n} *(\frac{n}{e} )^n

Because here we are taking the limit when n tends to infinity, we can use this approximation.

Then we get.

\lim_{n \to \infty} \frac{\sqrt[n]{n!} }{n} = \lim_{n \to \infty} \frac{\sqrt[n]{\sqrt{2*\pi*n} *(\frac{n}{e} )^n} }{n} =  \lim_{n \to \infty} \frac{n}{e*n} *\sqrt[2*n]{2*\pi*n}

Now we can just simplify this, so we get:

\lim_{n \to \infty} \frac{1}{e} *\sqrt[2*n]{2*\pi*n} \\

And we can rewrite it as:

\lim_{n \to \infty} \frac{1}{e} *(2*\pi*n)^{1/2n}

The important part here is the exponent, as n tends to infinite, the exponent tends to zero.

Thus:

\lim_{n \to \infty} \frac{1}{e} *(2*\pi*n)^{1/2n} = \frac{1}{e}*1 = \frac{1}{e}

7 0
3 years ago
What is the average speed between 2 seconds and 8 seconds.
Gennadij [26K]
Add the two speeds together, then divide the two, this gives the average speed. Hope this was helpful!
7 0
3 years ago
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In a famous story, a wise man in India requests a reward promised by his king. The wise man shows the king a chessboard having 6
Helen [10]
It is very large quantity....and can't be predicted.....and as I am from India ....I guess the whole kingdom rice will be not enough !!!

as the number will go trillion trillion !!!
6 0
3 years ago
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Equation of elimination method<br> 4a+b=28<br> a+4b=-8
Vilka [71]
Download an app called Photomath then it will answer it for you with work and explaining
6 0
3 years ago
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