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lozanna [386]
3 years ago
7

"Mia jogs 3 kilometers in 20 minutes. There are about 0.6 miles in a kilometer. What is Mia’s approximate speed in miles per min

ute?
A. 0.25 miles per minute
B. 0.09 miles per minute
C. 4 miles per minute
D. 11 miles per minute"
Mathematics
1 answer:
Nataly [62]3 years ago
4 0
B. 0.09 miles per minute
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The average daily rainfall for the past week in the town of Hope Cove is normally distributed, with a mean rainfall of 2.1 inche
natita [175]

Answer:

D

Step-by-step explanation:

We calculate the z-score for each

Mathematically;

z-score = (x-mean)/SD

z1 = (1.9-2.1)/0.2 = -1

z2 = (2.3-2.1)/0.2 = 1

So the proportion we want to calculate is;

P(-1<x<1)

We use the standard score table for this ;

P(-1<x<1) = P(x<1) -P(x<-1) = 0.68269 which is approximately 68%

6 0
3 years ago
PLEASE HELP
vodka [1.7K]
Proportional mate try that maybe then
6 0
3 years ago
The force newton(N),between two particles is inversely propotional to the square of the distance ,d m,between them.When particle
bonufazy [111]

Answer: 1.6\ N

Step-by-step explanation:

Given

The force between the two particles is inversely proportional to the distance between them

\Rightarrow F\propto \dfrac{1}{d^2}

When the distance is 2 m, the force is 10 N. For 5 m distance, it is

\Rightarrow \dfrac{10}{F_o}=\dfrac{5^2}{2^2}\\\\\Rightarrow F_o=10\times \dfrac{2^2}{5^2}\\\\\Rightarrow F_o=1.6\ N

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6 0
2 years ago
The electronics company makes two types of switches. Type a takes 4 minutes to make and requires $3 worth of materials.Type b ta
Shalnov [3]



Let

x ------> number of switch type A

y -----> number of switch type B

so

Remember that

1 hour=60 min

32 hours=32*60=1,920 minutes

4x+5y=1,920 -------> equation 1

3x+5y=1,740 ------> equation 2

Solve the system of equations

Solve by graphing

using a graphing tool

see the attached figure

Solution is

x=180

y=240

therefore

<h2>the number of switch type A was 180</h2><h2>the number of switch type B was 240</h2>

3 0
1 year ago
A particular fruit's weights are normally distributed, with a mean of 405 grams and a standard deviation of 19 grams. If a fruit
cluponka [151]

Answer:

413.126

Step-by-step explanation:

Given a normal distribution :

Mean (m) = 405

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Weight of fruit will be greater than how many grams (x) if picked 17% of the time:

P(Z > x) = 0.17 ;

The Zscore for P(Z > x) = 0.17 equals 0.954 (Z probability calculator)

Zscore = (x - m) / s

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x = 18.126 + 405

x = 423.126

Weight will be greater than 423.126

8 0
3 years ago
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