Answer:
r=1/π
Step-by-step explanation:
Area of the circle is defined as:
Area = πr²
Derivating both sides
=2πr
=
x
= 2πr
If area of an expanding circle is increasing twice as fast as its radius in linear units. then we have : =2
Therefore,
2πr = 2
r=1/π
Answer:
Step-by-step explanation:
Given that there is a function of x,
Let us find first and second derivative for f(x)
When f'(x) =0 we have tanx = 1 and hence
a) f'(x) >0 for I and III quadrant
Hence increasing in
and decreasing in
Hence f has a maxima at x = pi/4 and minima at x = 3pi/4
b) Maximum value =
Minimum value =
c)
f"(x) =0 gives tanx =-1
are points of inflection.
concave up in (3pi/4,7pi/4)
and concave down in (0,3pi/4)U(7pi/4,2pi)