Y = e^tanx - 2
To find at which point it crosses x axis we state that y= 0
e^tanx - 2 = 0
e^tanx = 2
tanx = ln 2
tanx = 0.69314
x = 0.6061
to find slope at that point first we need to find first derivative of funtion y.
y' = (e^tanx)*1/cos^2(x)
now we express x = 0.6061 in y' and we get:
y' = k = 2,9599
Answer:
0.98732
Step-by-step explanation:
Given that :
Mean = 10 minutes
Variance = 2 minutes
For less than equal 40 jobs
Mean (m) = 40 * 10 = 400 minutes
Variance = 2 * 40 = 80 minutes
Standard deviation (s) = √variance = √80
Converting hours to minutes
X = 60 * 7 = 420 minutes
P(X≤ 420) :
Z = (x - m) / s
P(X≤ 420) :
Z = (420 - 400) / √80
Z = 20 / √80 = 20 / 8.9442 = 2.236
P(Z ≤ 2.236) = 0.98732
Answer:
the correct for this question is be over the y-axis (x,y)=(-x,y)
