-7x + 6 = 27
-7x = 21 (Subtract 6 from both sides)
x = -3 (Divide -7 from both sides)
As x = 5 & z=12,
<span>2/3 = y /(xz) = y/(5*12) </span>
<span>= y/60 </span>
<span>so y / 60 = 2/3 </span>
<span>y = (2*60)/3 </span>
<span>= 40</span>
Answer:
First step, add 11 to 44.
Step-by-step explanation:
After that, divide both sides by negative 3.
The two containers hold 328 ounces at the they hold same amount of water.
<u>Step-by-step explanation:</u>
The equations below model the ounces of water, y, in each container after x minutes.


At the time after the start when the containers hold the same amount of water, the two equations must be equal.
⇒
The first step is to divide everything by 2 to make it simplified.
⇒ 
Now put everything on the left
.

Add the like terms together to further reduce the equation

Factorizing the equation to find the roots of the equation.
Here, b = -12 and c = -28
where,
- b is the sum of the roots ⇒ -14 + 2 = -12
- c is the product of the roots ⇒ -14 × 2 = -28
- Therefore, (x-14) (x+2) = 0
- The solution is x = -2 or x = 14
Take x = 14 and substitute in any of the given two equations,
⇒ 
⇒ 
⇒ 328 ounces
∴ The two containers hold 328 ounces at the they hold same amount of water.
To solve this problem, let us first assign variables. Let
us say that:
A = runner
B = cyclist
d = distance
v = velocity
time = t
The time in which the cyclist overtakes the runner is the
time wherein the distance of the two is the same, that is:
dA = dB
We know that the formula for calculating distance is:
d = v t
therefore,
vA tA = vB tB
Further, we know that tA = tB + 2, therefore:
vA (tB + 2) = vB tB
4 (tB + 2) = 14 tB
4 tB + 8 = 14 tB
10 tB = 8
tB = 0.8 hours = 48 min
Therefore the cyclist overtakes the runner after 0.8
hours or 48 minutes.