$-2x-14=7x+6\\\\\mathrm{Add\:}14\mathrm{\:to\:both\:sides}\\-2x-14+14=7x+6+14\\\\Simplify\\-2x=7x+20\\\\\mathrm{Subtract\:}7x\mathrm{\:from\:both\:sides}\\-2x-7x=7x+20-7x\\\\Simplify\\-9x=20\\\\\mathrm{Divide\:both\:sides\:by\:}-9\\\frac{-9x}{-9}=\frac{20}{-9}\\\\x=-\frac{20}{9}\\\left(\mathrm{Decimal}:\quad x=-2.22222\dots \right)\\x =-2.2$

7 0

3 years ago

Read 2 more answers

If y + 2q = 15, q + 2p = 5 and p + 2y = 7, then ﬁnd<br> the value of p + q + y.

notsponge [240]

$y+2q=15\\
y=15-2q\\\\
p+2y=7\\
p+2(15-2q)=7\\
p+30-4q=7\\
-3q+30=7\ \ \ |Subtract\ 30 \\
-3q=-23\ \ \ |Divide\ by\ -3\\
q=\frac{23}{3}\\\\
y=15-2q=15-2(\frac{23}{3})=15-\frac{29}{3}=15-7=8\\\\
p=7-2y\\
p=7-2*8\\
p=7-16=-9\\\\
\textbf{p+q+y=}-9+\frac{23}{3}+8=-1+7\frac{2}{3}=\boxed{6\frac{2}{3}}
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5 0

3 years ago

Ralphie has a large tropical fish collection. He gives 2/3 of his fish to a local high school. Then he gives 2/5 of the remainin

Lubov Fominskaja [6]

Let initially number of fishes =x

He gives 2/3 of his fish to a local high school, that is he gives 2x/3 fish .

So number of fishes left = x -(2x/3) = x/3 . And he gives 2/5 of x/3 to an elementary school , that is , he gives 2x/15 fishes to the elementary school. And finally the number of fishes left =30 , that is

$x-(\frac{2x}{3}+\frac{2x}{15})=30$