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Kaylis [27]
3 years ago
9

Each Club member collected 15 boxes of recycling for community service. Let c represent the number of club members and T represe

nts two total number of boxes collected. Which equation models the situation?
Mathematics
2 answers:
In-s [12.5K]3 years ago
7 0

Answer: If each member of the club collected 15 boxes, and you have C members in your club, then the total amount of boxes collected is 15*C boxes.

if you wanted to write "the" instead of "two"; then T = 15*C.

if you wanted to write "twice" instead of "two"; then T = 2*15*C = 30*C.

TEA [102]3 years ago
3 0
The equation is (assuming you meant the instead of two): T = 15c
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<u>Answer:</u>

Beto will get to the school first.

<u>Step-by-step explanation:</u>

We are given that Delia lives 3/4 mile from school and walks at a pace of

16 minutes per mile.

So Delia takes \frac{3}{4} \times 16 = 12 minutes to reach school.

While Beto lives 3 1/2 miles from school  and bikes at a pace of 3 minutes per mile.

So Beto takes \frac{7}{2} \times 3 = 10.5 minutes to reach school.

Therefore, Beto will get to the school first.

5 0
3 years ago
Combine the like terms to create an equivalent expression. <br><br> 7x−x
Alina [70]

Hello from MrBillDoesMath!

Answer:

6x

Discussion:

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So both terms are "like" terms in x:

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3 0
3 years ago
Jacob and issac decided to run to the basketball court after school the basketball court is 5 1/4 Miles from school the boys run
GenaCL600 [577]

Answer: 1\dfrac{5}{9}\text{ minutes}

Step-by-step explanation:

Complete question is provided in the attachment below.

Given: Jacob and Issac decided to run to the basketball court

Distance between basketball court and school = 5\dfrac{1}{4} miles

=\dfrac{21}{4} miles

Speed = 3\dfrac{3}{8} miles per hour

=\dfrac{27}{8} miles per hour

Since, time = (distance) ÷ ( speed)

Now, the time taken by boys to arrive at the basketball court = \dfrac{21}{4}\div\dfrac{27}{8} hours

=\dfrac{21}{4}\times\dfrac{8}{27}\\\\=\dfrac{7\times2}{9}=\dfrac{14}{9}\\\\=1\dfrac{5}{9}\text{ minutes}

Hence, the required length of time = 1\dfrac{5}{9}\text{ minutes}

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3 years ago
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3 years ago
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lara31 [8.8K]

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3 years ago
Read 2 more answers
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