Answer:
(x-4)² + y² = 100
Step-by-step explanation:
The only circles that have a center at (4 , 0) are :
(x-4)² + y² = 100
(x-4)² + y² = 10
……………………
• (-2 - 4)² + 8² = (-6)² + 64 = 36 + 64 = 100 ≠ 10
Then
The circle (x-4)² + y² = 10 doesn’t contain the point (-2, 8)
• (-2 - 4)² + 8² = 100
Then
The circle (x-4)² + y² = 100 contains the point (-2, 8)
Answer:
i do not know the answer to your question
Answer:
Step-by-step explanation:
J is a tangent to the circle and it is at right angle,
So applying Pythagorean theorem
HK² = KJ² + HJ²
HK² = 8²+ 15²
HK² = 64 + 225
HK² = 289
HK = √289
HK = 17 mi
Should be <span>10.75, 11.5, 12.25, 13, 13.75, 14.5</span>
