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4 years ago

Use the graph to answer the question what is the average rate from change from x=3 to x=11

Mathematics

1 answer:

expeople1 [14]4 years ago

7 0

Answer:

-1/8

Step-by-step explanation:

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I need help on my question plz help!!!!!!!!!!!!!!!!!! Thx

anzhelika [568]

What is the question to your problem though

7 0

3 years ago

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Jett has a large empty container, as shown below.

Marrrta [24]

Answer:

120 cubic inches

Step-by-step explanation:

12*4*5=240

240/2=120

6 0

3 years ago

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What steps would you use to plot (−3, −4, 0) in a 3-dimensional coordinate system?

eimsori [14]

Answer:

a. From the origin, move back 3 units and down 4 units

Step-by-step explanation:

Given:

The coordinates of a point in a 3-dimensional space is given as:

(-3, -4, 0)

The value of 'x' = -3

The value of 'y' = -4

The value of 'z' = 0

At the origin, the values of 'x', 'y', and 'z' are each equal to 0.

So, the coordinates of origin is (0, 0, 0). In order to reach the point (-3, -4, 0) from the point (0, 0, 0), we don't move along the z-axis as the 'z' value remains the same. We need to move along the 'x' and 'y' directions only.

Now, 'x' is equal to -3. Negative values of 'x' occur backwards from origin. So, we move back by 3 units. to reach the point (-3, 0).

Now, the value of 'y' is -4. Negative values of 'y' occur below the origin. So, we move down by 4 units to reach the point (-3, -4).

Therefore, the correct option is option (a)

A graph in 2 dimensional is shown in support of the answer.

8 0

4 years ago

The area of an 14-cm-wide rectangle is 322 cm2. What is its length? The length is cm.

Anika [276]

Answer:

The length of rectangle is 23 cm.

Step-by-step explanation:

DIAGRAM :

$\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(5,0){2}{\line(0,1){3}}\multiput(0,0)(0,3){2}{\line(1,0){5}}\put(0.03,0.02){\framebox(0.25,0.25)}\put(0.03,2.75){\framebox(0.25,0.25)}\put(4.74,2.75){\framebox(0.25,0.25)}\put(4.74,0.02){\framebox(0.25,0.25)}\multiput(2.1,-0.7)(0,4.2){2}{\sf\large{14\ cm}}\multiput(-1.4,1.4)(6.8,0){2}{\sf\large{14\ cm}}\put(-0.5,-0.4){\bf}\put(-0.5,3.2){\bf}\put(5.3,-0.4){\bf}\put(5.3,3.2){\bf}\end{picture}$

$\begin{gathered}\end{gathered}$

SOLUTION :

Here's the required formula to find the length of rectangle :

${\longrightarrow{\pmb{\sf{A_{(Rectangle)} = l \times b}}}}$

A = Area
l = length
b = breadth

Substituting all the given values in the formula to find the length of rectangle :

$\begin{gathered}\qquad{\longrightarrow{\sf{A_{(Rectangle)} = l \times b}}}\\\\\qquad{\longrightarrow{\sf{322 = l \times 14}}}\\\\\qquad{\longrightarrow{\sf{322 = 14l}}}\\\\\qquad{\longrightarrow{\sf{l = \dfrac{322}{14}}}}\\\\\qquad{\longrightarrow{\sf{l = \cancel{\dfrac{322}{14}}}}}\\\\\qquad{\longrightarrow{\sf{l = 23 \: cm}}}\\\\\qquad{\star{\underline{\boxed{\sf{ \pink{l = 23 \: cm}}}}}}\end{gathered}$

Hence, the length of rectangle is 23 cm.

$\begin{gathered}\end{gathered}$

LEARN MORE :

$\boxed{\begin {minipage}{9cm}\\ \dag\quad \Large\underline{\bf Formulas\:of\:Areas:-}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length\times Breadth \\\\ \star\sf Triangle=\dfrac{1}{2}\times Breadth\times Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Rhombus =\:\dfrac {1}{2}p\sqrt {4a^2-p^2}\\ \\ \star\sf Parallelogram =Breadth\times Height\\\\ \star\sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \star\sf Equilateral\:Triangle=\dfrac {\sqrt{3}}{4}(side)^2\end {minipage}}$

$\rule{300}{2.5}$

6 0

2 years ago

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Is this 1/3 7/21 a proportion

Brut [27]

Yes they are proportionate

3 0

3 years ago

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