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Karo-lina-s [1.5K]
3 years ago
6

Find the dimensions of a deck which will have railings on only three sides. There is 28 m of railing available and the deck must

be as large as possible.
Mathematics
1 answer:
Roman55 [17]3 years ago
5 0

Answer:

The largest possible area of the deck is 87.11 m² with dimensions;

Width = 9.33 m

Breadth = 9.33 m

Step-by-step explanation:

The area of a given dimension increases as the dimension covers more equidistant dimension from the center, which gives the quadrilateral with largest dimension being that of a square

Given that the railings will be placed on three sides only and the third side will cornered or left open, such that the given length of railing can be shared into three rather than four to increase the area

The length of the given railing = 28 m

The sides of the formed square area by sharing the railing into three while the fourth side is left open are then equal to 28/3 each

The area of a square of side s = s²

The largest possible area of the deck = (28/3)² = 784/9 = 87.11 m² with dimensions;

Width = 28/3 m = 9.33 m

Breadth = 28/3 m = 9.33 m.

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nata0808 [166]
4u^2+28u+49=4u^2+14u+14u+49=2u(u+7)+7(u+7)=\\ \\=(u+7)(2u+7)
3 0
2 years ago
If AB=BC,AB=4=4x-2,andBC=3x+3,fine the length of AB
laila [671]

Answer:

18

Step-by-step explanation:

First, I'm assuming AB=4=4x-2 was a typo and it's supposed to be AB = 4x - 2

AB=BC

AB = 4x - 2 BC = 3x + 3

4x - 2 = 3x + 3

Solve for x Add 2 to each side

4x - 2 = 3x + 3

4x - 2 + 2 = 3x + 3 + 2

4x = 3x + 5 Subtract 3x from each side.

4x - 3x = 3x- 3x + 5

4x - 3x = 5

x = 5

Now plug back in to the original equations

AB = 4x - 2                  BC = 3x + 3

AB = 4 (5) - 2               BC = 3(5) + 3

AB = 20 - 2                  BC = 15 + 3

AB = 18                        BC = 18

So AB is 18

3 0
3 years ago
Suppose KLMN ~ PQRS. Find the value of x.
arlik [135]

Complete question is attached.

Answer:

B) 8

Step-by-step explanation:

In this question, KLMN ~ PQRS. This means they are similar shapes.

From the image, we could denote that:

KL ~ PQ

LM ~ QR

Given that:

KL = 12

PQ = 30

QR = 20

LM = x

To find x, let's use tge expression:

\frac{KL}{PQ} = \frac{LM}{QR}

=  \frac{12}{30} = \frac{x}{20}

Cross multiplying, we have:

12 * 20 = 30x

240 = 30x

To find x, let's divide both sides by 30.

\frac{240}{30} = \frac{30x}{30}

8 = x

x = 8

The correct option is option B.

3 0
3 years ago
Answer ALL if u cant see all the answers it don't matter all u need is the question
bekas [8.4K]
I'm probably wrong but I think A.
4 0
2 years ago
Log(x+6)-log(x-3)=1<br><br> I need to show work, please show me how
Illusion [34]

Answer:

x = 4.

Step-by-step explanation:

log(x + 6)- log(x - 3) = 1

Using the law log a - log b = log a/b:

log (x + 6)/ (x - 3) = 1

Removing logs:

(x + 6)/ (x - 3) = 10

x+ 6 = 10x - 30

9x = 36

x = 4 (answer).

8 0
3 years ago
Read 2 more answers
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