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kogti [31]
3 years ago
13

Determine the y-intercept of the graph.

Mathematics
1 answer:
Georgia [21]3 years ago
6 0

Answer:

Your y intercept is 1.

Step-by-step explanation:

slope is y2-y1 over x2-x1, or 2.

slope intercept formula is y=mx+b, and if you plug values into formula you get 3=2(1)+b

and if you solve that, 2x1=2, 3-2=1.

then you get 1 as your y intercept.

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Help fast plz give me the answer
Lunna [17]
The answer is 75 degrees I believe.

45 + 60 + x = 180

I’m pretty sure I’m correct but I’m so sorry if I’m wrong.
7 0
3 years ago
A square has an area o 38 cm. How long to one of to dites?
yKpoI14uk [10]
9.5
and
9

a square has 4 sides and i’m ~assuming~ they’re equilateral, so take the area and divide it by 4.

im not 100% sure but maybe this will help a little bit!! :)
4 0
3 years ago
Find the distance from the origin to the graph of 7x+9y+11=0
Cerrena [4.2K]
One way to do it is with calculus. The distance between any point (x,y)=\left(x,-\dfrac{7x+11}9\right) on the line to the origin is given by

d(x)=\sqrt{x^2+\left(-\dfrac{7x+11}9\right)^2}=\dfrac{\sqrt{130x^2+154x+121}}9

Now, both d(x) and d(x)^2 attain their respective extrema at the same critical points, so we can work with the latter and apply the derivative test to that.

d(x)^2=\dfrac{130x^2+154x+121}{81}\implies\dfrac{\mathrm dd(x)^2}{\mathrm dx}=\dfrac{260}{81}x+\dfrac{154}{81}

Solving for (d(x)^2)'=0, you find a critical point of x=-\dfrac{77}{130}.

Next, check the concavity of the squared distance to verify that a minimum occurs at this value. If the second derivative is positive, then the critical point is the site of a minimum.

You have

\dfrac{\mathrm d^2d(x)^2}{\mathrm dx^2}=\dfrac{260}{81}>0

so indeed, a minimum occurs at x=-\dfrac{77}{130}.

The minimum distance is then

d\left(-\dfrac{77}{130}\right)=\dfrac{11}{\sqrt{130}}
4 0
3 years ago
Can anyone solve this for me pls
svetlana [45]

Answer: I'm pretty sure the answer is 78.90

Step-by-step explanation:

8 0
2 years ago
choose a non-piecewise function f(x) such that it’s Domain is all x≤5. Find the values of your function for x={−2,−1,0,1,2,3,4,5
iren2701 [21]

Answer:

f(x) = √(5-x)

Step-by-step explanation:

The square root is only defined for non-negative arguments. Here, we give it an argument that is only non-negative for x ≤ 5, thus satisfying the requirement for your function. The attached shows a table of values and a graph of it.

3 0
3 years ago
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