dy/dx = 8(8x - 5)(4x² - 5x )^ 7
differentiate using the ' chain rule '
dy/dx = 8(4x² - 5x)^ 7 × d/dx (4x² - 5x)
= 8(4x² - 5x)^ 7 × (8x - 5)
= 8(8x - 5)(4x² - 5x)
If the width of a rectangle is x + 2 and the length is twice as long, what is the area?
1 answer:
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