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Slav-nsk [51]
3 years ago
12

Two consecutive integers have a sum of 73. Find the integers.

Mathematics
2 answers:
Lelechka [254]3 years ago
6 0

Hi!

x + x + 1 = 73

2x + 1 = 73

2x = 72

x = 72/2

x = 36

x+1 = 37

Hope this helps!

patriot [66]3 years ago
4 0

<u>Here's how to do it using algebra:</u>

Let the smaller integer be 'x' .  Then the larger integer is (x+1).

Their sum is (x) + (x+1).

That's (2x + 1) .

The problem says their sum is 73, so we can write . . . 2x + 1 = 73 .

Subtract 1 from each side . . . 2x = 72

Divide each side by 2 . . . x = 36

The smaller integer is 36 .

The larger integer is (x+1) .  That would be 37.

The two consecutive integers are  <em>36 </em> and  <em>37</em> .

_______________________________________

<u>Here's how to do it using your brain:</u>

-- If they were both the same number, then their sum would be double it, and each integer would be half of  73 .

-- That's 36.5 .

-- But  36.5  is not even an integer, so neither integer can be 36.5.  Is there something we can do to a pair of 36.5s to make them whole numbers (integers), make them different, and make them consecutive, but not let their sum change ?

-- Well, if we slice off a piece from one of them and glue it onto the other one, then we'll wind up with two numbers that are different, and their sum won't change.

-- What happens if we take the  .5  off of one of them and glue it onto the other one ?   Then one of the 36.5s shrinks to become  <u>36</u>, and the other one grows to become  <u>37</u> .

-- Well whaddaya know !  Now we have two numbers that are consecutive integers, and they add up to  73 .  Great move !

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