<span>–vp + 40 < 95
-vp < 55
-vp < 55 / p
v > 55 / p</span>
Answer:
Step-by-step explanation:
y![f(x)^{-1} = inverse\\f(x)=y \\y = 1/(x^{3} \\Inverse: y=x ------------> x = 1/y^{3}\\y^{3} - \frac{1}{x} = 0\\y^{3} = \frac{1}{x}\\y = \sqrt[3]{\frac{1}{x}} \\y = \frac{\sqrt[3]{1} }{\sqrt[3]{x}} \\y = \frac{1}{\sqrt[3]{x}}](https://tex.z-dn.net/?f=f%28x%29%5E%7B-1%7D%20%20%3D%20inverse%5C%5Cf%28x%29%3Dy%20%5C%5Cy%20%3D%201%2F%28x%5E%7B3%7D%20%5C%5CInverse%3A%20y%3Dx%20------------%3E%20x%20%3D%201%2Fy%5E%7B3%7D%5C%5Cy%5E%7B3%7D%20-%20%5Cfrac%7B1%7D%7Bx%7D%20%3D%200%5C%5Cy%5E%7B3%7D%20%3D%20%5Cfrac%7B1%7D%7Bx%7D%5C%5Cy%20%3D%20%5Csqrt%5B3%5D%7B%5Cfrac%7B1%7D%7Bx%7D%7D%20%5C%5Cy%20%3D%20%5Cfrac%7B%5Csqrt%5B3%5D%7B1%7D%20%7D%7B%5Csqrt%5B3%5D%7Bx%7D%7D%20%5C%5Cy%20%3D%20%5Cfrac%7B1%7D%7B%5Csqrt%5B3%5D%7Bx%7D%7D)
So hmmm let's see
she has a monthly income of 120 from investments, now, there are 12 months in a year, so her yearly income from investments are 120*12 or
$1440
she plays on a band, and makes 200 a week, now, there are 52 weeks in a year, so her yearly income from band playing is 200 * 52, or
$10400
her total annual income is 49696, now, if we subtract the band and investment income, we'd be left over with only what comes from her job payrate
so 49696 - 1440 - 10400 is 37856
so, she makes from her job, $37856 annually
now, she only works 28 hours weekly, how much is that yearly? well, 52 weeks in a year, she works 28*52 hours a year, let us divide 37856 by that
37856 ÷ ( 28 * 52) well, it ends up as 26
so, her hourly payrate is $26 per hour
now, she wants to ask for a raise, to make 51880 annually
well, if we check the difference of 51880 and 49696, that'd leave us with the difference in pay, or the raise annual amount
51880 - 49696 = 2184
ok, so she wants $2184 annually more from her work
how much is that in the hours she works annually? well 2184 ÷ ( 28 * 52)
Answer:
34.83
Step-by-step explanation:
