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Goryan [66]
3 years ago
10

If a 1 =6 and a n =-2a n-1 a 5 then find the value of a5

Mathematics
1 answer:
tekilochka [14]3 years ago
5 0

Answer:

a₅ = 96

Step-by-step explanation:

We know that:

a₁ = 6

aₙ = -2*aₙ₋₁

Then we want to find the value of a₅

We can do it in two ways, we can use the relation to find the terms as:

a₂ = -2*a₁ = -2*6 = -12

a₃ = -2*a₂ = -2*(-12) = 24

a₄ = -2*a₃ = -2*24 = -48

a₅ = -2*a₄ = -2*(-48) = 96

Then we have a₅ = 96

And we know that this is a geometric sequence, where the ratio between terms is -2, then the n-th term can be written as:

aₙ = a₁*r^(n - 1)

where r is the ratio, in this case, r = -2 and a₁ = 6

Then:

aₙ = 6*(-2)^(n -1)

then:

a₅ = 6*(-2)^(5 - 1) = 6*(-2)^4 = 96

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8/x=14/7 what does x equal
Veronika [31]

Answer:

when you have two fractions that equal each other you want to solve by using cross multiply

What cross multiply is, is when you multiply diagonally so:

8/x=14/7

you would take 14*x and 8*7

14x=56 (you would then divide each side by 14)

x=4 (14/14=1, 56/14=4)

8/4=14/7

To check your work you could simplify

8/4=2

14/7=2

2=2, which is true

x=4

Hope this helps ;)

6 0
3 years ago
!!!!Which ordered pair in the form of (x, y) are solutions to the equation 7x - 5y =28
muminat

Answer:

(-6,-14)

Step-by-step explanation:


8 0
3 years ago
a fruit delivers its fruit in two types of boxes: large and small. a delivery of 3 large boxes and 5 small boxes has a total wei
Masteriza [31]

Answer:

The weight of a small box  = 13.5 kg

The weight of 1 large box = 18.5 kg

Step-by-step explanation:

Let us assume the weight of a small box = m kg

And the weight of 1 large box  = n kg

Now, the weight of 5 small box = 5 x (weight of 1 small box) =  5 m

Also, the weight of 3 large box = 3 x (weight of 1 large box) =  3 n

Here,   3 large boxes +  5 small boxes =  of 123 kilograms

⇒ 5  m + 3 n = 123   .... (1)

Again, the weight of 2 small box = 2 x (weight of 1 small box) =  2 m

Also, the weight of 12 large box = 12 x (weight of 1 large box) =  12 n

Here,   12 large boxes +  2 small boxes =  249 kilograms

⇒ 2 m+ 12 n = 249   .... (2)

Now, solving both the given equations by ELIMINATION, we get:

5  m + 3 n = 123     x (2)

2 m+ 12 n = 249     x (-5)

we get the new set of equitation as:

10 m + 6 n = 246

- 10 m - 60 n =  -1245

Adding both equation, we get

-54 n = 999

or, n = 18.5

Now, 5  m + 3 n = 123

So, 5 m = 123  -3 (18.5)  = 123 - 55.5 =  67.5

⇒  m = 13.5

Hence,  the weight of a small box = m kg = 13.5 kg

And the weight of 1 large box = n kg  = 18.5 kg

8 0
3 years ago
Suppose p" must approximate p with relative error at most 10-3 . Find the largest interval in which p* must lie for each value o
goblinko [34]

Answer:

[p-|p|*10^{-3} \, , \, p+|p|* 10^-3]

Step-by-step explanation

The relative error is the absolute error divided by the absolute value of p. for an approximation p*, the relative error is

r = |p*-p|/|p|

we want r to be at most 10⁻³, thus

|p*-p|/|p| ≤ 10⁻³

|p*-p| ≤ |p|* 10⁻³

therefore, p*-p should lie in the interval [ - |p| * 10⁻³ , |p| * 10⁻³ ], and as a consecuence, p* should be in the interval  [p - |p| * 10⁻³ , p + |p| * 10⁻³ ]

8 0
3 years ago
Based on this graph, what would the cost to refill 50 bottles
Elis [28]

Answer:

175

Step-by-step explanation:

for 10 water bottles its 35 dollars so you multiply 10 by 5 and its 50. so you multiply 35 by 5 and get 175.

3 0
3 years ago
Read 2 more answers
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